<span>1 X 25 + 1 X 24 + 1 X 23 + 0 X 22 + 1 X 21 + 1 X 20 thus your Answer is C</span>
Explanation:
"Select vendor_name as Vendor_Name,
default_account_number as Default_Account_No ,
account_description as Account_Description
From Vendors v, General_Ledger_Accounts ledger
where (add the join condition here)
Order by account_description, vendor_name"
Note: In the above statement, include the alias name appropriately and then execute the query
The "select statement" should contain the list of columns to be displayed
"From statement" should contain the name of the table from which data needs to be fetched.
"Where clause" defines the relationship as well the condition that needs to be executed
"Order by clause" defines the sorting mechanism with the relevant field
Answer:
See explaination for the code
Explanation:
def wordsOfFrequency(words, freq):
d = {}
res = []
for i in range(len(words)):
if(words[i].lower() in d):
d[words[i].lower()] = d[words[i].lower()] + 1
else:
d[words[i].lower()] = 1
for word in words:
if d[word.lower()]==freq:
res.append(word)
return res
Note:
First a dictionary is created to keep the count of the lowercase form of each word.
Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.
Finally the res list is appended.
Answer:
Explanation:
The following is a python function that has arrays with all the cards available and then uses random to choose a random card from the dictionary. Finally it prints out the card chosen...
import random
def choose_card():
card = ["Ace", 2, 3, 4, 5, 6, 7, 8, 9, 10, 'Jack', 'Queen', 'King']
symbols = ['Clubs', 'Diamonds', 'Hearts', 'Spades']
chosen_card = str(card[random.randint(0, len(card))])
symbols = symbols[random.randint(0, len(symbols))]
print("Chosen Card: " + chosen_card + " of " + symbols)
