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3 years ago

Cuantoi es 5 elevado a la 3

2 answers:

6 0

Tendría que ser el número 5 es más grande pero el número 3 tendría que tener poder masivo en los negativos o positivos o posiblemente ambos

Mars2501 [29]3 years ago

3 0

La risposta es 125
5 x 5=25
25 x 5=125

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The width of a rectangle is 12 units. Can the perimeter x of the rectangle can be 60 units when its length y is 18 units? (1 poi

juin [17]

If the width is 12 and the length is 18, the perimeter of the rectangle is 12 + 12 + 18 + 18, or 60. So yes the perimeter can be 60.

8 0

2 years ago

At Least One Defective iPhone It has been reported that 20% of iPhones manufactured by Foxconn for a product launch did not meet

bija089 [108]

We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.

7 0

3 years ago

Simplify. (h + 12) + (p +24) a) hp + 288 b) hp + 36 c) 12h + 24p d) h + p + 36

KIM [24]

(h+12) + (p+24)

h+p+12+24 = h+p+36

8 0

2 years ago

Read 2 more answers

A debate team of 4 members for a high school will be chosen randomly from a potential group of 15 students. Ten of the 15 studen

iragen [17]

Answer:

A) 0.1538

Step-by-step explanation:

4 members are going to be chosen:

M1 - M2 - M3 - M4

We have to find the probability that for each member, one without experience is chosen. There is no replacents.

Initially, we have 15 students, of which 10 have none experience. So the probability that M1 is chosen as a student with no experience is $\frac{10}{15}$ .

Then, there are 14 students, of which 9 have no experience. So the probability that M2 is chosen as a student with no experience is $\frac{9}{14}$ .

For the third member, there are 13 students, of which 8 have no experience. So the probability that M3 is chosen as a student with no experience is $\frac{8}{13}$ .

For the last member, there are 12 students, of which 7 have no experience. So the probability that M4 is chosen as a student with no experience is $\frac{7}{12}$ .

What is the probability that none of the members chosen for the team have any competition experience?

This is

$P = \frac{10}{15}*\frac{9}{14}*\frac{8}{13}*\frac{7}{12} = 0.1538$

The correct answer is:

A) 0.1538

7 0

3 years ago

A taxi company charges a $2.00 base fare plus an additional fare based on a per-mile rate and a per-minute rate. Ryan's first ta

Fed [463]

A $2.00 base fare charge, and per-mile, and per-minute rates related as follows; 3•x + 7•y = 6.5 and 7•x + 14•y = 14, give the distance traveled in the third ride as 4.5 miles

<h3>How can the length of the third ride be calculated?</h3>

The base fare = $2.00

Let x represent the per-mile rate, and let y represent the per-minute rate, we have;

The cost of Ryan's first taxi ride = $8.50

Distance traveled in the first ride = 3.0 miles

Time taken during the first ride = 7 minutes

Therefore;

2 + 3•x + 7•y = 8.5

Which gives;

3•x + 7•y = 8.5 - 2 = 6.5

3•x + 7•y = 6.5...(1)

Distance traveled in the second ride = 7.0 miles

Duration of the second ride = 14 minutes

The second ride cost = $16.00

Therefore;

2 + 7•x + 14•y = 16

Which gives;

7•x + 14•y = 16 - 2 = 14

7•x + 14•y = 14...(2)

Solving the above simultaneous equations by multiplying equation (1) by 2 then subtracting the result from equation (2) gives;

(7•x + 14•y) - 2 × (3•x + 7•y) = 14 - 2×6.5 = 1

x = 1

The per-mile rate, x = $1

3•x + 7•y = 6.5

7•y = 6.5 - 3•x

7•y = 6.5 - 3×1 = 3.5

y = 3.5/7 = 1/2 = 0.5

The per-minute rate, y = $0.5

Duration of the third taxi ride = 10 minutes

Cost of the third ride = $13.50

Therefore;

2 + 1×a + 10×y = $13.50

Where a is the distance traveled during the third ride, we have;

2 + 1×a + 10×0.5 = $13.50

2 + a + 5 = 13.5

a = 13.5 - 2 - 7 = 4.5

The third ride was, a = 4.5 miles

Learn more about simultaneous linear equations here:

brainly.com/question/24085666

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3 0

1 year ago