Is there any induced current in the pickup coil when the polarity of the bar magnet is flipped?
1 answer:
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Answer:
(a). The reactive power is 799.99 KVAR.
(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.
Explanation:
Given that,
Power factor = 0.6
Power = 600 kVA
(a). We need to calculate the reactive power
Using formula of reactive power
...(I)
We need to calculate the
Using formula of
Put the value into the formula
Put the value of Φ in equation (I)
(b). We draw the power triangle
(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95
Using formula of reactive power
We need to calculate the difference between Q and Q'
Put the value into the formula
Hence, (a). The reactive power is 799.99 KVAR.
(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.
a) The distance of the image from the mirror is 15 cm
b) The size of the image is -2 cm (inverted)
Explanation:
a)
We can solve this first part of the problem by applying the mirror equation:
where
f is the focal length
p is the distance of the object from the mirror
q is the distance of the image from the mirror
For a mirror, the focal length is half the radius of curvature, R:
For this mirror, R = 20 cm, so its focal length is
(positive for a concave mirror)
Here we also know:
p = 30 cm is the distance of the object from the mirror
So, by applying the equation, we can find q:
b)
We can solve this part by using the magnification equation:
where
y' is the size of the image
y is the size of the object
q is the distance of the image from the mirror
p is the distance of the object from the mirror
Here we have:
q = 15 cm
p = 30 cm
y = 4 cm
Solving for y', we find the size of the image:
and the negative sign means that the image is inverted.
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