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3 years ago

Solve the following problems, giving the answers to the proper number of sig figs.

Chemistry

1 answer:

Pie3 years ago

5 0

Answer:

a.20.988m

b.21.74m

c.221652000

d.23 200kg/m^3

e.121.159

f.349.47m

g.0.43489

h.2.59108e-7

i.0.00168550368

j.76330

k.74.98764 liters

l.0.008199

plzzzzz mark me as brainliest this took me 4 hours

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HELPPPPP WILL MARK DOWN BRAINLIEST TOPIC: gravity

pshichka [43]

Explanation:

1. Newton's universal law of gravitation states that every particle in the universe attracts every other particle with a force along a line joining them. The force is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

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4 0

3 years ago

Please help me for question 1 and 2

likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0

3 years ago

A solution of barium ions and silver ions what could be the anion

Tems11 [23]

Nitrate only. Niritate is anion.

3 0

3 years ago

What is the sum of the fractions 2/9+5/9

RUDIKE [14]

Answer:

7\9

Explanation:

please marl brainlieat

6 0

3 years ago

An alternative definition of electronegativity is Electronegativity= constant (I.E — E.A.) where I.E. is the ionization energy a

Kazeer [188]

Answer:

The electronengativity values of given elements is as follows.

Fluorine - 4

Chlorine -3

Bromine - 2.9

Iodine- 2.5

Explanation:

Electronegativity =consant (I.E-E.A)

The electron affinity and ionization energy values of the given elements is as follows.

(In attachment)

First we have to find the value of constant by using the fluorine atom to whom the electronengativity taken as "4".

Fluorine:

$4=constant[1678-(-327.8)]$

$Constant=0.0019942168$

By using this constant values we can find electronegatvity values of remaining elements.

Chlorine:

$Electronegativity=0.0019942168[1255+348.7]=3.1980\sim 3$

Therefore, electronegativity of chlorine is 3.

Bromine:

$Electronegativity=0.0019942168[1138+324.5]=2.91\sim 2.9$

Therefore, electronegativity of bromine is 2.9.

Iodine:

$Electronegativity=0.0019942168[1007+295.7]=2.59\sim 2.5$

Therefore, electronegativity of iodine is 2.5.

8 0

3 years ago