Given :
A 10.99 g sample of NaBr contains 22.34% Na by mass.
To Find :
How many grams of sodium does a 9.77g sample of sodium bromine contain.
Solution :
By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.
Therefore , percentage of Na by mass in NaBr will be same for every amount .
Percentage of Na in 9.77 g NaBr is 22.34 % too .
Gram of Na = 
.
Hence , this is the required solution .
<span>Two scientists wrote a paper detailing their research and conclusions and submitted it to a scientific journal. Several months later, they received the paper back from the publisher with many comments attached from several fellow scientists. It is either that they revise their study or replicate the study. Most scientists would revisit their work and the findings they had from their research. Most probable if they were successful and the comments of the publisher and the co-scientists were positive they could replicate the study to validate its accountability.<span>
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I believe the statement above is true. The stronger the wind, the larger the particles it erodes<span>. The stronger the wind, the larger the particles that are carried away.
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The density is mass divided by volume
Answer:
The molecular formula of X is C8H9NO2
Explanation:
Step 1: Data given
exact mass of 151.0640
Molar mass of C = 12 g/mol
Molar mass of H = 1.00783 g/mol
Molar mass of O = 15.9949 g/mol
Molar mass of N = 14.0031 g/mol
Step 2: Calculate molar mass of C7H5NO3
7*12 + 5*1.00783 + 14.0031 + 3*15.9949 = 151.02695 g/mol
Step 3: Calculate molar mass of C8H9NO2
8*12 + 9*1.00783 + 14.0031 + 2*15.9949 = 151.06337 g/mol
Step 4: Calculate molar mass of C10H17N
10*12 + 17*1.00783 + 14.0031 = 151.13621 g/mol
The molecular formula of X is C8H9NO2
