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prisoha [69]
3 years ago
5

Two varible which have a constant ratio between them are said to be

Mathematics
1 answer:
slamgirl [31]3 years ago
5 0

Answer:

Step-by-step explanation:

A proportional

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01: Which gives the correct order of steps needed to multiply the problem below? 83 X 39 O Multiply the ones. 8 times 39 is 312.
Burka [1]

Answer:

Multiply the ones. 9 times 83 is 747. Multiply the tens. 30 times 83 is 2,490. Add the products to get 3,237.

The rest of the question:

Which gives the correct order of steps needed to multiply the problem below?   "83x39 "

The steps to multiply  83x39

1) multiply the ones 9 times 83 = 9 times 3 + 9 times 80 = 27 + 720 = 747

2) multiply the tens 30 times 83 = 30 times 3 + 30 times 80 = 90 + 2400 = 2490

3) add 747 and 2490 = 747 + 2490 = 3,237

According to the previous steps, the answer is option 3

Multiply the ones. 9 times 83 is 747. Multiply the tens. 30 times 83 is 2,490. Add the products to get 3,237.

6 0
4 years ago
Read 2 more answers
A student, taking a true- false test, randomly guesses at every one
Ann [662]

Answer:

32

Step-by-step explanation:

Each question has 2 possible sets of answers, so multiply the number of possible answers by how many answers there is and you get 32.

7 0
2 years ago
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Evaluate the expression when a is -5 and y is 7<br> a-5y
Sonbull [250]

Answer:

The answer is -40

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • a = -5
  • y = 7
<h3><u>To </u><u>Find</u>;</h3>
  • a – 5y

Now,

a – 5y

(-5) – 5(7)

-5 – 35 = -40

Thus, The answer is -40

<u>-TheUnknownScientist</u><u> 72</u>

8 0
3 years ago
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D. -6.24, -4.03, -1.82, 0.39, ... Find the 20th term.
Gemiola [76]

Answer:

the 20th term of the sequence is 35.75

6 0
3 years ago
Factor 4x^4yz-16y^3z
Iteru [2.4K]

Answer:

<h2>4x⁴yz - 16y³z = 4yz(x² - 2y)(x² + 2y)</h2>

Step-by-step explanation:

4x^4yz-16y^3z\\\\4x^4yz=4yz\cdot x^4\\\\16y^3z=4yz\cdot4y^2\\\\4x^4yz-16y^3z=4yz\cdot x^4-4yz\cdot4y^2=4yz(x^4-4y^2)\\\\x^4-4y^2=x^{2\cdot2}-2^2y^2=(x^2)^2-(2y)^2=(x^2-2y)(x^2+2y)\\\\Used:\\\\(a^n)^m=a^{nm}\\\\(ab)^n=a^nb^n\\\\a^2-b^2=(a-b)(a+b)\\\\4x^4yz-16y^3z=4yz(x^2-2y)(x^2+2y)


6 0
3 years ago
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