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3 years ago

If y varies directly as x and y=288 when x=16 determine the value of y when x-13

1 answer:

5 0

Y = kx is the direct variation equation
Substitute the x and y that are given to find k then write your new equation in terms of y with the k.

288 = k(16) divide by 16 to find k
18 = k
Now write the new equation
y = 18x

y = 18(13) or y = 18(-13) I'm not sure by what you have typed if that is supposed to be and equal sign or a negative.
y = 234 OR y = -234

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We can’t understand how to find the pattern

cupoosta [38]

Answer:

Pattern: subtract 2 from the input to get the output

When the input is 9, the output is 7

When the input is 13, the output is 11

Step-by-step explanation:

» <u>Application + Solution</u>

To find the pattern, we have to look for common things we notice between the input and output.

After analyzing, we can surely notice that we subtract two from the input each time to get the output because 3 - 2 = 1, 8 - 2 = 6, 15 - 2 = 13, and 20 - 2 = 18.

Now that we realized the pattern, we subtract 2 from 9 and 13.

9 - 2 = 7
13 - 2 = 11

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2 years ago

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ankoles [38]

Answer:

8 ================================================================ D

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Step-by-step explanation:

3 0

3 years ago

(3,y) (1,4) m= -2 what is the value of y if the line through the two given points is to have indicated slope

riadik2000 [5.3K]

Answer:

y=0

Step-by-step explanation:

The equation for the slope is

m = ( y2-y1)/(x2-x1)

-2 = (4-y)/(1-3)

-2 = (4-y)/-2

Multiply each side by -2

4 = 4-y

Subtract 4 from each side

4-4 = 4-y-4

0 = -y

0=y

5 0

3 years ago

Write (-5+8i)+(-5-8i) as a complex number in standard form

gizmo_the_mogwai [7]

$(-5+8i)+(-5-8i) =
-5+8i-5-8i=-10$

5 0

3 years ago

3. if kx² + 2x + k = -kx have equal roots, find the values of k.<br>

crimeas [40]

Answer:

k = - $\frac{2}{3}$ , k = 2

Step-by-step explanation:

Using the discriminant Δ = b² - 4ac

The condition for equal roots is b² - 4ac = 0

Given

kx² + 2x + k = - kx ( add kx to both sides )

kx² + 2x + kx + k = 0 , that is

kx² + (2 + k)x + k = 0 ← in standard form

with a = k, b = 2 + k and c = k , thus

(2 + k)² - 4k² = 0 ← expand and simplify left side

4 + 4k + k² - 4k² = 0

- 3k² + 4k + 4 = 0 ( multiply through by - 1 )

3k² - 4k - 4 = 0 ← in standard form

(3k + 2)(k - 2) = 0 ← in factored form

Equate each factor to zero and solve for k

3k + 2 = 0 ⇒ 3k = - 2 ⇒ k = - $\frac{2}{3}$

k - 2 = 0 ⇒ k = 2

5 0

4 years ago