All categories

3 years ago

If y varies directly as x and y=288 when x=16 determine the value of y when x-13

1 answer:

5 0

Y = kx is the direct variation equation
Substitute the x and y that are given to find k then write your new equation in terms of y with the k.

288 = k(16) divide by 16 to find k
18 = k
Now write the new equation
y = 18x

y = 18(13) or y = 18(-13) I'm not sure by what you have typed if that is supposed to be and equal sign or a negative.
y = 234 OR y = -234

You might be interested in

Saturday, nola bowled 3 games in her bowling league. she had a mean score of 115. the score of her first game was 110. the score

Elina [12.6K]

110+90+145=345
345 divided by 3=115

so the score of her third game was 145 points.
hope i helped! :)
please rate brainliest!

7 0

3 years ago

Read 2 more answers

Evaluate the summation of negative 2 n minus 3, from n equals 2 to 10..

Alisiya [41]

$\bf \sum\limits_{n=2}^{10}~-2n-3$

so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".

however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus k = n - 1.

however, if k = n - 1, then k + 1 = n. So let's use those fellows then,

$\bf \sum\limits_{n=2}^{10}~-2n-3\qquad 
\begin{cases}
k=n-1\\
k+1=n
\end{cases}\implies \sum\limits_{k=1}^{9}~-2\stackrel{n}{(k+1)}-3
\\\\\\
\sum\limits_{k=1}^{9}~-2k-2-3\implies \sum\limits_{k=1}^{9}~-2k-5\implies \sum\limits_{k=1}^{9}~-2k-\sum\limits_{k=1}^{9}~5
\\\\\\
-2\sum\limits_{k=1}^{9}~k-\sum\limits_{k=1}^{9}~5\implies -2\left( \cfrac{9(9+1)}{2} \right)\qquad -\qquad (9\cdot 5)
\\\\\\
-2(45)-45\implies -90-45\implies -135$

5 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

astra-53 [7]

$\sqrt{5}$

5 0

3 years ago

What is the inverse of x^2-4x+5

lisabon 2012 [21]

we are given

$f(x)=x^2-4x+5$

Since, we have to find inverse of this function

step-1: we set f(x)=y

$y=x^2-4x+5$

step-2: switch x and y

$x=y^2-4y+5$

step-3: Solve for y

$y^2-4y+(5-x)=0$

now, we can use quadratic formula

$y=\frac{4+\sqrt{4^2-4(5-x)} }{2}$

$f^{-1}(x)=\sqrt{x-1}+2$

$f^{-1}(x)=-\sqrt{x-1}+2$ ..............Answer

6 0

3 years ago

So far, Ricardo has scores of 13, 17, 19 and 21 points for the first four rounds of a dice game. What does he need the total sco

posledela

Answer:

40 points

Step-by-step explanation:

The score for the first four rounds of the game is 13, 17, 19, and 21 points.

Let $S_5$ and $S_6$ be the scores of the fifth and sixth games respectively in order to achieve an average score of 20 points per round for all six rounds.

$\text{Average score} = \frac{\text{Sum of the scores of all the rounds}}{\text{Total number of the rounds}}$

$\Rightarrow 20=\frac{13+17+19+21+S_5+S_6}{6}$

$\Rightarrow 20\times6=80+S_5+S_6$

$\Rightarrow S_5+S_6=120-80=40.$

Hence, the combined score of the fifth and sixth rounds are 40 points.

3 0

4 years ago