Answer:
-6/5
Step-by-step explanation:
You are going down 6 units and 5 units to the direction of the point you get .
Standard form of equation is to be defined as: to write the equation of a line in standard form. Definitions: Standard Form: the standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers
Answer:
Step-by-step explanation:
Let the speed of Masha = s, speed of Dasha = d
- Distance = 20 km
- Time difference = 20 min = 1/3 hr
- Speed difference = 2 km/h
<u>As per above info we get following equations:</u>
- s = d + 2
- 20/s + 1/3 = 20/d
<u>Substitute s and solve for d:</u>
<u>Get rid of fraction by multiplying all terms by 3d(d + 2):</u>
- 60d + d(d + 2) = 60(d + 2)
- 60d + d² + 2d = 60d + 120
- d² + 2d = 120
- d² + 2d + 1 = 121
- (d + 1)² = 11²
- d + 1 = 11
- d = 10
<u>Find s:</u>
<u>The answer is</u>
- Masha's speed 12 km/h and Dasha's speed 10 km/h
Hey!
The first step to solving this problem would be to distribute the parenthesis. We do this so that we can get rid of the parenthesis.
<em>Original Equation :</em>
5 ( x - 10 ) = 30 - 15x
<em>New Equation {Changed by Distribution} :</em>
5x - 50 = 30 - 15x
The next step would be to 50 to both sides. The reason we do that is to get rid of the 50 that is on the left side of the equation.
<em>Old Equation :</em>
5x - 50 = 30 - 15x
<em>New Equation {Changed by Adding 50 to Both Sides} :</em>
5x = 80 - 15x
And now we would add 15x to both sides to get rid of the -15x on the right side of the equation.
<em>Old Equation :</em>
5x = 80 - 15x
<em>New Equation {Changed by Adding 15x to Both Sides} :</em>
20x = 80
Now we divide both sides by 20 to get x on it's own.
<em>Old Equation :</em>
20x = 80
<em>New Equation {Changed by Dividing Both Sides by 20} :</em>

=

Finally, all we have to do is solve to find x.
<em>Old Equation :</em>

=

<em>Solution {Old Equation Solved} :</em>
x = 4
<em>So, in the equation </em><span><em>5 ( x – 10 ) = 30 – 15x</em>,
x = 4.
Hope this helps!
- Lindsey Frazier ♥</span>
The answer to the question