Answer:
Part a) The solution is the ordered pair (6,10)
Part b) The solutions are the ordered pairs (7,3) and (15,1.4)
Step-by-step explanation:
Part a) we have
----> equation A
----> equation B
Multiply equation A by 10 both sides to remove the fractions
----> equation C
isolate the variable y in equation B
----> equation D
we have the system of equations
----> equation C
----> equation D
Solve the system by substitution
substitute equation D in equation C

solve for x

Multiply by 3 both sides


Combine like terms


<em>Find the value of y</em>


The solution is the ordered pair (6,10)
Part b) we have
---> equation A
----> equation B
isolate the variable x in the equation B
----> equation C
substitute equation C in equation A

solve for y


Solve the quadratic equation by graphing
The solutions are y=1.4, y=3
see the attached figure
<em>Find the values of x</em>
For y=1.4

For y=3

therefore
The solutions are the ordered pairs (7,3) and (15,1.4)