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liq [111]
3 years ago
9

3. In chickens, the frizzle gene “F” controls the appearance of the feathers. A homozygous dominant chicken for the frizzle gene

shows “extreme frizzle”, that is his feathers are extremely disrupted. The normal chicken is homozygous recessive and has undisrupted feathers. When a chicken with extreme frizzle is mated with a normal chicken, all of the offspring exhibit mild frizzle.
Biology
1 answer:
Nezavi [6.7K]3 years ago
3 0
I am not sure how this is a questions but the explanation is correct.
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Flowers are a collection of _____ tissue produced by some plants.
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There are choices for this question namely:

1. Sterile
2. Reproductive
3. Both
4. Neither

The correct answer is that flowers are a collection of reproductive tissue produced by flowering plants (angiosperms). The flower is a reproductive organ of the plant. It is composed of the male organ (stamen) which produces the pollen and the female organ (ovary) which receives the pollen. Once the ovary receives the pollen either from the same plant or from another through pollination, the ovule (part of the ovary) will then become the seed and the ovary will become the fruit. The seed is the "embryo" of the plant wherein if planted, it will grow to a new plant. 
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2. Skeletal muscle:
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The answer is D, all of the above.
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3 years ago
Eukaryotes that are not closely related and that do not share many anatomical similarities can still be placed together on the s
Svetradugi [14.3K]
<h2>Homologous genes get Highly Conserved</h2>

Explanation:

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  • Fungi such as Mushrooms
  • Protists such as Paramaecium
  • Amoeba are the examples of Eukaryotes.
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8 0
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SOMETHING I DONT UNDERSTAND! My sis told me she was on her perio d but then I told her there was this thing called subject and p
shusha [124]

Answer:

yep life tends to not make sense

i feel you gurl i also have a older sister

Explanation:

8 0
3 years ago
What is the probability that the first offspring from the cross listed below will be heterozygous for all loci?
Tanya [424]

Answer and Explanation:

<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee

We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:

1) aa     x     AA

F1) 4/4=1 Aa

2) Bb    x    bb

F1) ½ bb

     ½ Bb

3) dd    x    Dd

F1) ½ dd

     ½ Dd

4) Ee    x    Ee

F1) ¼ EE

    2/4 = ½ Ee

     ¼ ee

So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:  

1 Aa   x   ½ Bb   x    ½ Dd    x    ½ Ee = 1/8 AaBbDdEe

                                 

6 0
3 years ago
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