Answer:
here
Explanation:
Heterozygous male with type blood A has the genotype of IA IO. Heterozygous female with blood type B has the genotype of IB IO.
Crossing IA IO × IB IO;
25% IA IB - blood type AB
25% IA IO - blood type A
25% IB IO - blood type B
25% IO IO - blood type O
One one side of the Punnet Square, label B. The other, Label b. Take the upper right corner for example. The solution would be Bb.