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skelet666 [1.2K]
3 years ago
6

Please help on this physics question?

Physics
1 answer:
Anton [14]3 years ago
5 0
W=F*d

W=-60N*5m=-300J

So friction does -300J of work on the box
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A quantity of gas has a volume of 0.20 cubic meter and an absolute temperature of 333 degrees kelvin. When the temperature of th
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Answer:

Option C is the correct answer.

Explanation:

By Charles's law we have

        V ∝ T

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       \frac{V_1}{T_1}=\frac{V_2}{T_2}

Here given that

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Substituting

      \frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{0.20}{333}=\frac{V_2}{533}\\\\V_2=\frac{0.20}{333}\times 533=0.3198m^3

New volume of the gas  = 0.3198 m³

Option C is the correct answer.

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