an athlete sprints from 150 m south of the finish line to 65 m south of the finish line in 5.0s what is his average velocity

Physics

2 answers:

MatroZZZ [7]3 years ago

6 0

Total displacement=150-65m=85m
Time=5s

$\\ \rm\longrightarrow Avg\:Velocity=\dfrac{Total\:Displacement}{Total\:Time}$

$\\ \rm\longrightarrow Avg\:Velocity=\dfrac{85}{5}$

$\\ \rm\longrightarrow Avg\:Velocity= 17m/s$

ladessa [460]3 years ago

5 0

Answer:

$displacement = 150 - 65 = 85m \: \\ time = 5sec \\ velocity = displacement/ time= \frac{85}{5} = 17 \frac{m}{s} \: south\\ thank \: you$

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Where:

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