Question

an athlete sprints from 150 m south of the finish line to 65 m south of the finish line in 5.0s what is his average velocity

Answer 1

• Total displacement=150-65m=85m
• Time=5s

$\\ \rm\longrightarrow Avg\:Velocity=\dfrac{Total\:Displacement}{Total\:Time}$

$\\ \rm\longrightarrow Avg\:Velocity=\dfrac{85}{5}$

$\\ \rm\longrightarrow Avg\:Velocity= 17m/s$

Answer 2

Answer:

$displacement = 150 - 65 = 85m \: \\ time = 5sec \\ velocity = displacement/ time= \frac{85}{5} = 17 \frac{m}{s} \: south\\ thank \: you$