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2 years ago

an athlete sprints from 150 m south of the finish line to 65 m south of the finish line in 5.0s what is his average velocity

Physics

2 answers:

MatroZZZ [7]2 years ago

6 0

Total displacement=150-65m=85m
Time=5s

$\\ \rm\longrightarrow Avg\:Velocity=\dfrac{Total\:Displacement}{Total\:Time}$

$\\ \rm\longrightarrow Avg\:Velocity=\dfrac{85}{5}$

$\\ \rm\longrightarrow Avg\:Velocity= 17m/s$

ladessa [460]2 years ago

5 0

Answer:

$displacement = 150 - 65 = 85m \: \\ time = 5sec \\ velocity = displacement/ time= \frac{85}{5} = 17 \frac{m}{s} \: south\\ thank \: you$

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Answer:

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$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, the law of conservation of linear momentum takes the form:

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If both masses stick together after the collision at a common speed v', then:

$m_1v_1+m_2v_2=(m_1+m_2)v'$

The car of mass m1=1000 Kg travels at v1=25 m/s and collides with another car of m2=1500 Kg which is at rest (v2=0).

Knowing both cars stick and move together after the collision, their velocity is found solving for v':

$\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}$

$\displaystyle v'=\frac{1000*25+1500*0}{1000+1500}$

$\displaystyle v'=\frac{25000}{2500}$

v' = 10 m/s

The velocity of the two cars is 10 m/s after the collision.

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