he product side of a chemical reaction is shown. → 7Ti2(SO4)3 Which number represents a coefficient? 2 3 4 7

The dispatcher of courier service receives a message from truck A that reports a position of +5 after a displacement of +2. What

Romashka [77]

The formula we need to use is displacement.

$d=\Delta{x}=x_f-x_i$ , where xf is final position and xi is initial position.

We report the final position of 5 and the displacement of 2 so the formula is now:

$2=5-x_i\Longrightarrow x_i=3$ .

So the initial position of truck A is 3.

Hope this helps.

r3t40

8 0

3 years ago

A projectile enters a resisting medium at x = 0 with an initial velocity v0 = 910 ft/s and travels 5 in. before coming to rest.

evablogger [386]

Answer:

a = - 1.987 × 10⁶ ft/s²

t = 6.84 × 10⁻⁴ s

Explanation:

v₀ = 910 ft/s

x = 5 in.

relation v = v₀ - k x

v = 0 as body comes to rest

0 = 900 - 5k/12

k = 2184 s⁻¹

acceleration

$\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}$

where

(A) a = -k × v

at v= 910 ft/s

a = - 1.987 × 10⁶ ft/s²

(B) at x = 3.9 in.

v = 910 - 3.9(2184)/12

v = 200.2 m/s

$\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}$

$\frac{dv}{v} = -kdt$

$\int\limits^{200.2}_{900} {\frac{1}{v} }dv = -k\int\limits^t_0 dt$

$ln(200.2)-ln(900) = -kt$

t = 6.84 × 10⁻⁴ s

3 0

3 years ago

Un prisma rectangular de cobre, de base igual a 36 centímetros cuadrados y una altura de 10 cm se sumerge hasta la mitad por med

butalik [34]

La respuesta correcta es 180 centímetros cúbicos o 180 $cm^{3}$

Explicación:

El primer paso para saber cuanto alcohol desaloja el prisma es calcular el volumen total del prisma. El volumen se puede encontrar usando la formula V (Volumen) = B (base) x h (altura). El proceso se muestra a continuación:

V = B x h

V = 36 $cm^{2}$ x 10 cm

V= 360 $cm^{3}$

Finalmente, el volumen total del prisma debe dividirse en 2 considerando que solo la mitad del prisma fue sumergida y esta mitad equivale al volumen del alcohol desplazado.

360 $cm^{3}$ ÷ 2 = 180 $cm^{3}$

5 0

2 years ago

I need help with this question I’m not sure where to even begin

Strike441 [17]

We will have the following:

a. We determine the tension force of T2 as follows:

We know that the system must be at equilibrium on the horizontal axis:

$\sum F_x=T_1cos(42.5)+T_2cos(36.5)=0$

So:

$\begin{gathered} T_2cos(36.5)=-(1235N)cos(42.5)\Rightarrow T_2=-\frac{(1235N)cos(42.5)}{cos(36.5)} \\ \\ \Rightarrow T_2=1132.711003...N\Rightarrow T_2\approx1132.7N \end{gathered}$

So, the value of T2 is approximately 1132.7 N.

b. We will determine the torques created by T1 and T2 as follows:

T1:

$\tau_{T1}=(10m)(1235N)sin(42.5)\Rightarrow\tau_{T1}\approx8343.5N\ast m$

T2:

$\tau_{T2}=(10m)(1132.7N)sin(36.5)\Rightarrow\tau_{T2}\approx6737.6N\ast m$

So the torques of T1 and T2 on the base are approximately 8343.5 N*m and 6737.6 N*m respectively.

c. The torques around that axis generated by the normal force and the weight are both 0 N*, since they are parallel to the axis.

d. We will determine the angular acceleration as follows:

$\begin{gathered} \alpha=\frac{\tau_{T1}}{I}\Rightarrow\alpha=\frac{\tau_{T1}}{(1/3mL^2)} \\ \\ \Rightarrow\alpha=\frac{(8343.5N\ast m)}{(1/3(200kg)(10m)^2)}\Rightarrow\alpha=1.251525rad/s^2 \\ \\ \Rightarrow\alpha\approx1.25rad/s^2 \end{gathered}$

So, the angular acceleration is approximately 1.25 radians/ s^2.

6 0

1 year ago

Elements in the periodic table are arranged in order of increasing...

Radda [10]

Answer:

(B) The number of protons - only the number of protons in the nucleus determines the element - mass and neutrons can vary for the same element

4 0

2 years ago