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3 years ago

Question 4 (1 point)

Mathematics

2 answers:

djyliett [7]3 years ago

7 0

2 rice/4.5 water = 5 rice/x water

Multiply by x water and get

X 0.44 rice =5rice

Now divide by rice

X=11.25 rice

Alja [10]3 years ago

4 0

Answer:

11.25

Step-by-step explanation:

water/rice

4.5/2=n/5

2*n=2n

4.5*5=22.5

22.5=2n

/2 /2

11.25=n

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

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3 years ago

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xenn [34]

Answer:

m∠1 = 50°

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Explanation:

m∠2 = 130° because of alternate exterior angles.

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NARA [144]

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TIME CRUCIAL!! i will give you thanks please help!!! ASAP! will mark as brainliest!!

ozzi

$\overline{y}$ (prounounced "y bar") is the mean of the y values

Add up the y values to get
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Then divide by 5 (because there are five y values) to get
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Therefore,
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3 years ago