All categories

3 years ago

Tomas needs exactly 6 potatoes to make 12 potato

Mathematics

2 answers:

alexandr1967 [171]3 years ago

7 0

Answer:

A,B,D

12/24=0.5

18/36=0.5

30/60=0.5

By the slash I mean divide

Hope this helps

Step-by-step explanation:

Marina86 [1]3 years ago

6 0

Answer:

Options A , B and D

Step-by-step explanation:

Tomas needs exactly 6 potatoes to make 12 pancakes

So, the rate will be 12/6 = 2

We will check the options:

A) Tomas needs exactly 12 potatoes to make 24 potato pancakes.

Rate = 24/12 = 2

B) Tomas needs exactly 18 potatoes to make 36 potato pancakes.

Rate = 36/18 = 2

C) Tomas needs exactly 24 potatoes to make 44 potato pancakes.

Rate = 44/24 = 1.833

D) Tomas needs exactly 30 potatoes to make 60 potato pancakes.

Rate = 60/30 = 2

E) Tomas needs exactly 36 potatoes to make 78 potato pancakes.

Rate = 78/36 = 2.1667

So, the answers are:

Options A , B and D

You might be interested in

Whats the answers??????????????

Aleonysh [2.5K]

the arrows pointing to 36

8 0

3 years ago

Read 2 more answers

Need help asap answering no 2 and 4

aleksandr82 [10.1K]

For 2, AB is parallel to CD as AD is also parallel to BC

For 3, you can also say AD is parallel to BC

7 0

4 years ago

Read 2 more answers

If VW≅VY, WX = s + 69, and XY = 4s, what is the value of s?

Katen [24]

Answer:

s = 23

Step-by-step explanation:

1. VW ≅ VY is given.

2. XV ≅ VX as it is the same side.

3. ∠WVX ≅ ∠YVX as they are both 90°. ∠WVY is 180° as it is a straight line, so both ∠WVX and ∠YVX are exactly half of that.

Given those three things, you can say that ΔWVX ≅ ΔYVX. Because all corresponding parts of congruent triangles are also congruent, you can be sure that WX ≅ XY. Finally, using that information, you can write an equation and solve for s.

$s+69=4s\\s-s+69=4s-s\\69=3s\\\frac{69}{3}=\frac{3s}{3}\\s=23$

7 0

3 years ago

Let X be from a geometric distribution with probability of success p. Given that P(X > y) = (1 ???? p)y for any positive inte

nevsk [136]

Full Question

Let X be from a geometric distribution with probability of success p.

Given that P ( X > a + b | X > a ) = q ^ { b } = P ( X > b ) for any positive integer x.

Show that for positive integers a and b, P(X > a + b | X > a) = P(X > b).

Answer:

P(X > a + b | X > a) = P(X > b)

Proved --- See Explanation

Step-by-step explanation:

Given

P ( X > a + b | X > a ) = q ^ { b } = P ( X > b )

From the above.

We can derive the following

P(X > a), P(X > b) and P(X > a + b)

P(X > a) = q^a

P(X > b) = q^b

P(X > a + b) = q^(a + b)

Using the definition of conditional probability

P(X > a + b | X > a) can be represented by P(X > a + b and X > a)/ P(X>a)

X>a+b and X>a is equivalent to X>a+b since a+b is larger than a

So,

P(X > a + b and X > a)/ P(X>a) can be rewritten as

P(X>a + b)/P(X > a)

Bringing both sides together, we're left with

P(X > a + b | X > a) = P(X>a + b)/P(X > a)

By substituton

P(X > a + b | X > a) = q^(a+b)/q^a

P(X > a + b | X > a) = q^(a + b - a)

P(X > a + b | X > a) = q^(a - a + b)

P(X > a + b | X > a) = q^b

Since P(X > b) = q^b

So,

P(X > a + b | X > a) = P(X > b)

4 0

3 years ago

ANSWER THE QUESTIONS PLEASE IT IS ON BEARING

artcher [175]

9514 1404 393

Answer:

(i) x° = 70°, y° = 20°

(ii) ∠BAC ≈ 50.2°

(iii) 120

(iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

x = 70

The angle marked y° is the supplement to the one marked 160°.

y = 20

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

tan(∠BAC) = BC/BA = 120/100 = 1.2

∠BAC = arctan(1.2) ≈ 50.2°

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

(iv) The bearing of A from C is 180 added to the bearing of C from A:

120 +180 = 300

The three-digit bearing of A from C is 300.

8 0

3 years ago