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kondor19780726 [428]
3 years ago
9

A sine function can be used to model light waves. Green light has a wave length, or period of about 510 nm . which equation best

models green light? a. y= sin pi/510 theta b. y= sin pi/255 theta c. y= sin 510/pi theta d. sin 255/pi theta
Mathematics
2 answers:
marin [14]3 years ago
7 0
<span>A sine function can be used to model light waves. Green light has a wave length, or period of about 510 nm. The equation that best models green light is </span><span>y= sin 510/pi theta. The answer is letter C.</span>
Monica [59]3 years ago
5 0

Answer:

y=\sin(\frac{\pi \theta}{255})

B is correct.

Step-by-step explanation:

A sine function can be used to model light waves. Green light has a wave length, or period of about 510 nm .

Equation of sine wave:

y=\sin(ax)

As we know the period of sine function is 2π

Period of this function y=\sin(ax) is 2π/a

We are given the period of function is 510

Thus, 510=\dfrac{2\pi}{a}

Now we will solve for a

a=\dfrac{2\pi}{510}

a=\dfrac{\pi}{255}

Required equation: y=\sin(\frac{\pi \theta}{255})

Hence, The equation for best models green light is y=\sin(\frac{\pi \theta}{255})

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Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

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Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

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2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

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2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

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Solving:

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4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

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