Question 1:
Slope = 1/5
y = mx + c
y = 1/5 x + c
at point (5, -1)
-1 = 1/5 (5) + c
- 1= 1 + c
c = - 2
y = 1/5x - 2
5y = x - 10
Question 2:
slope = (9-5)/(3-1)
Slope = 2
y = mx + c
y = 2x + c
at point (1, 5)
5 = 2(1) + c
c = 5 - 2
c = 3
y = 2x + 3
Ok so domain is all allowed numbers
look at deonomenator and don't allow any numbers that will make it zero
none
that means
domain=all real numbers
vertex
in form
y=a(x-h)^2+k
(h,k)=vertex
we have
y=-2(x+3)^2-1
h=-3
k=-1
vertex=(-3,-1)
range
the vertex opens down so max is y=-1
y≤-1
domain is all real
vertex is (-3,-1)
y≤-1
C
Step-by-step explanation:
-1,6 is -1 left 6 up
1,-6 is 1 right -6 down
6,-1 is 6 right -1 down
Two hundred ninety three thousand eight hundred and five
The answer would be: X=26
