Question

Somebody please help me with this !!!

Answer 1

Step-by-step explanation:

Case 1 :

$3x + 2y = 6 \\ 4x + y = 2 \\ 3x = 6 - 2y \\ x = \frac{6 - 2y}{3} = \\ x = 2 - \frac{2y}{3} \\ 4(2 - \frac{2y}{3} ) + y = 2 \\ 8 - \frac{8y}{3} + y = 2 \\ - 1.67y = - 6$

$y = 3.59 \\ x = 2 - \frac{2y}{3} \\x = 2 - \frac{2 \times 3.59}{3} \\ \\ x = - 0.39$

Case 2 :

$3x + 2y = 6 \\ 4x - y = 2 \\ x = 2 - \frac{2y}{3} \\ 4(2 - \frac{2y}{3} ) - y = 2 \\ 8 - \frac{8y}{3} - y = 2 \\ - 3.67y= - 6 \\ y = 1.63$

$x = 2 - \frac{2y}{3} \\ x = 2 - \frac{2 \times 1.63}{3} \\ x = 2 - 1.087 \\ x = 0.913$