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Slav-nsk [51]
1 year ago
5

Question 1 1.1 Jane wants to make Spaghetti Bolognese for her family of 5 people, including herself. The following is a list of

some of the ingredients used to make Spaghetti Bolognese (serving 2 people): 300g Minced Meat 1 Onion 1 Clove Garlic 2 Sticks Celery 1 Carrot 125g Mushrooms 50g Tomato Paste 400g Tomatoes 1,5dl Passata 1dl Water 0,5dl Red Wine 250g Spaghetti 100g Cheese Rosemary Thyme Oregano Bay Leaf O o O 1.1.1 Convert 300g to kg. (2) 1.1.2 How many kilograms of tomato will be needed to make this recipe for her family? (5) 1.1.3 500ml of water is needed to make the recipe. Convert this into litres. (2) 1.1.4 The pot that will be used to make this recipe has a radius of 7cm and a height of 5cm. using the conversion 1cm3 = 1 000ml, determine the capacity of the pot in litres. (Capacity =īt x radius x radius x height where a = 3,142) (5) 1.2 Jane's friend Amelia, visits from the United States. She gets a copy of the recipe but has to convert the recipe into imperial units. 1.2.1 If 1 kg = 2,2 lb (pounds), convert 300g into pounds. (3) 1.2.2 She uses 17,6056 fl. oz. of water for her recipe. If this is equivalent to 500ml, determine the conversion rate between fl. oz. and ml. Round off your answer to one decimal place. (4) 1.2.3 She will travel to Cape Town from Johannesburg during her trip. She estimates that the distance is approximately 500 miles between the two cities. If 1 mile = 1,609 km and the distance between Johannesburg and Cape Town is 810 km, determine if she is correct. (3) 1.2.4 The temperature when she arrived in Cape Town was 34 °Celsius. Convert this temperature to °Fahrenheit. (2) 1.3 If 1 cm3 = 1 ml and 1 000 cm° = 1 4. Determine the following: 1.3.1 How many cmare in 875 l ? (2) 1.3.2 How many t are there in 35,853 cm3? (2) [30] pyright reserved
Mathematics
1 answer:
Lelechka [254]1 year ago
8 0

Answer:

\begin{gathered} 1.1.1.300g\cdot\frac{0.001\operatorname{kg}}{1g}=0.3\operatorname{kg} \\ 1.1.2.400g\cdot\frac{0.001\operatorname{kg}}{1g}=0.4\operatorname{kg} \\ 1.1.3.500ml\cdot\frac{0.001lt}{1ml}=0.5\text{ lt} \\ 1.1.4.769.69\cdot0.001=0.769\text{ liters} \end{gathered}

Step by step explanation:

1.1.1 We know that 1kg is equivalent to 1000g, then we can convert:

300g\cdot\frac{0.001\operatorname{kg}}{1g}=0.3\operatorname{kg}

1.1.2 For 400g of tomatoes:

400g\cdot\frac{0.001\operatorname{kg}}{1g}=0.4\operatorname{kg}

1.1.3. For 500ml of water, convert this into liters. We know that a 1ml is 0.001 lt

500ml\cdot\frac{0.001lt}{1ml}=0.5\text{ lt}

1.1.4. Since capacity is represented by the following expression:

\begin{gathered} C=\pi\cdot\text{radius}\cdot\text{radius}\cdot\text{height} \\ C=\pi\cdot7\cdot7\cdot5=769.69cm^3 \end{gathered}

We know that 1 cubic centimeter is equal to 0.001 liters.

769.69\cdot0.001=0.769\text{ liters}

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Question 9 (1 point)
Romashka [77]

Answer:

Step-by-step explanation:

League A                   League B

151.12                            163.25

148                                157

26.83                             24.93

29                                  136

136                                145

167                                178

207                               256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(82.5-1.5\times 76.56,159.06+1.5\times 76.56)

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(140.5-1.5\times 30.125,170.625+1.5\times 30.125)

(95.3125,215.8125)

24.93 and 256 are outliers  

Maximum = 256

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2 1/7+3/7(3X-5) =-4
KATRIN_1 [288]

Answer:

what is the question?

Step-by-step explanation:

4 0
4 years ago
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Please help ASAP please and thank you have a great and blessed day!
goldenfox [79]
<
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is going to be your answers i believe
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3 years ago
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Pls help will give 5 stars and heart
Tamiku [17]
So the circle is 39.25
And the area of triangle 30 together about 39.25
5 0
3 years ago
6 lbs of potatoes cost $72. How many<br> lbs of potatoes can you get with $516?
Rasek [7]

Answer:

42

Step-by-step explanation:

516 divided by 72 = 7.1. You cant use .1 pound . Then you do 6*7 = 42 pounds of potatoes

8 0
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