Answer:
idk but heres an equation
Step-by-step explanation:
Since
2
π
r
=
37.68
,
r
=
18.84
π
Area=
π
⋅
(
18.84
)
2
π
2
=
354.9456
3.14
= 113.04
Yes, you are correct, because -2 is 2 spaces away from the number line.
-4 - 1/3=-4.33333333333<span>
-4 - -1=-3
1/3 - 2=</span>-1.66666666667<span>
1/3 - 3 1/2=</span>-3.16666666667<span>
2 - 3 1/2=</span>-1.5<span>
-1 - 3 1/2=</span><span>-4.5</span>
It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
Answer:
No
Step-by-step explanation:
Using the Pythagorean Theorem, make 40 = c, 24 = b and the remaining side (the width) = a.
Solving for a we get a = 
. Then plugging in the values for c and b, we get a = 
= 32
Since the width of the TV needs to be less than 30" wide, it will not fit since the width of the TV is 32" wide.
