Help please ASAP!!!!!!!!

An experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. How man

zheka24 [161]

Answer:

43,680 ways.

Step-by-step explanation:

We have been given that an experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. We are asked to find the number of groups of 4 participants that can be chosen, assuming that the order in which the participants are chosen is irrelevant.

We will use permutations formula to solve our given problem.

$^nP_r=\frac{n!}{(n-r)!}$

For our given problem $n=16$ and $r=4$ .

$^{16}P_4=\frac{16!}{(16-4)!}$

$^{16}P_4=\frac{16!}{12!}=\frac{16*15*14*13*12!}{12!}=16*15*14*13=43,680$

Therefore, 4 participants can be chosen in 43,680 different ways.

6 0

4 years ago

Lindsey sold stationery to her family and her mother's friends shw deposited the $125 shw earned in a savings account. The accou

Leona [35]

Your Answer will be: $134.71

8 0

3 years ago

Read 2 more answers

Mr lee's homeroom class won a pizza party withfive pizzas. The students ate 3 1/3 of the pizzas. How many pizzas are left?

algol13

A whole pizza has 3 x 1/3 pizzas.
So if you eat 3 of 5, 2 pizza lefts.
If you eat 1/3 from 2 pizzas, 1 and 2/3 pizzas left.

Hope this help. :)

3 0

3 years ago

Read 2 more answers

A balloon is blowing up at a constant rate of 9 cubic centimeters per second. When the volume of the balloon is 2048/3 pi cubic

jekas [21]

Answer:

$\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec$

Step-by-step explanation:

<u>Rates of Change as Derivatives</u>

If some variable V is a function of another variable r, we can compute the rate of change of one with respect to the other as the first derivative of V, or

$\displaystyle V'=\frac{dV}{dr}$

The volume of a sphere of radius r is

$\displaystyle V=\frac{4}{3}\pi r^3$

The volume of the balloon is growing at a rate of $9\ cm^3/sec$ . This can be written as

$\displaystyle \frac{dV}{dt}=9$

We need to compute the rate of change of the radius. Note that both the volume and the radius are functions of time, so we need to use the chain rule. Differentiating the volume with respect to t, we get

$\displaystyle \frac{dV}{dt}=\displaystyle \frac{dV}{dr}\displaystyle \frac{dr}{dt}$

$\displaystyle \frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}$

solving for $\displaystyle \frac{dr}{dt}$

$\displaystyle \frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2}$

We need to find the value of r, which can be obtained by using the condition that in that exact time

$\displaystyle V=\frac{2048}{3}\pi\ cm^3$

$\displaystyle \frac{2048}{3}\pi=\frac{4}{3}\pi r^3$

Simplifying and isolating r

$\displaystyle r^3=512$

$\displaystyle r=\sqrt[3]{512}=8\ cm$

Replacing in the rate of change

$\displaystyle \frac{dr}{dt}=\frac{9}{4\pi 8^2}$

$\displaystyle \frac{dr}{dt}=\frac{9}{256\pi }$

$\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec$

8 0

3 years ago

Can someone explain how this works and help me to find the answer?

pav-90 [236]

470 = 8.75(46 - c) + 11c
470 = 402.5 - 8.75c + 11c
67.5 = 2.25c
30 = c

If c = 30 and Soren worked 30 hours in the office, earning $11 per hour, he earns $330 from his office job. 46 - 30 = 16, which should be the remaining amount of hours Soren worked. 16 * 8.75 = 140. He earned $140 from his cashier job. $330 + $140 = $470.

The correct formula to solve this problem is A. 11c + 8.75(46 - c) = 470

8 0

3 years ago