Queremos ver que fracción de la finca se ha destinado a plazas de aparcamiento.
La solución es:
La fracción de la finca que se destina a plaas de aparcamiento es 3/56
Sabemos que originalmente se iba a destinar 3/14 del total de la finca a plazas de aparcamiento, pero finalmente se destino 3/4 de lo previsto a zonas ajardinadas.
Es decir, <u>se destino 3/4 de los 3/14 del total de la finca</u> a zonas ajardinadas, entonces <u>el 1/4 restante se dedico a plazas de aparcamiento</u>, esto da:
(1/4)*3/14 = 3/56
La fracción de la finca que se destina a plaas de aparcamiento es 3/56
Sí quieres aprender más, puedes leer:
brainly.com/question/16649102
If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
Answer:
Step-by-step explanation:
Area of the figure = Are of square with side 8 in + 2 times the area of one triangle with base (8 - 5 = 3) 3 in and height 4 in
Answer:
The correct option is 4.
Step-by-step explanation:
The given expression is
Simplify the given expression.
![[\because x^mx^n=x^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20x%5Emx%5En%3Dx%5E%7Bm%2Bn%7D%5D)
Therefore correct option is 4.
