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Illusion [34]
3 years ago
15

Inside a square with side length 10, two congruent equilateral triangles are drawn such that they share one side and each has on

e vertex on a vertex of the square. What is the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles?

Mathematics
1 answer:
Sphinxa [80]3 years ago
4 0

Answer:

5 length

Step-by-step explanation:

The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share  one side of the square  BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.

So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.

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Subtract 4/15 - 1/6. Simplify the answer.
damaskus [11]

Answer:

Find the smallest multiple the denominators have in common  

30

Expand each fraction so that the denominators are 30

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Add or subtract the numerators and keep the same denominator

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​  

 

​

7 0
2 years ago
6) A cube has a volume of 125 mm3, what is its surface area?<br> Volume = s3<br> Area = 6x s2
Elena L [17]
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Step-by-step explanation:

r³ = 125

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...

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3 0
3 years ago
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