Inside a square with side length 10, two congruent equilateral triangles are drawn such that they share one side and each has on
e vertex on a vertex of the square. What is the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles?
1 answer:
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
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Answer:
£6000
Step-by-step explanation:
Given:
Phillip Cage played, £21,000 was split at a ratio of 2:5 between the arena and Phillip Cage.
Question asked:
How much money did the arena make from Phillip Cage's concert?
Solution:
Ratio Arena and Philip cage in which money distributed = 2 : 5
Let ratio be
Money earned by Arena =
Money earned by Phillip Cage =
Phillip Cage played total for = £21,000
<u>Money earned by Arena + Money earned by Phillip Cage = £21,000</u>
Dividing both sides by 7
Money earned by Arena = =
Thus, Arena made £6000 from Phillip Cage's concert.
Answer:
y = 5 and y = 1
Step-by-step explanation:
⇒ (3y - 2)² + 7 - 7 = 43 - 7
⇒ (3y - 2)² = 36
⇒ √(3y - 9)² = √36
⇒ 3y - 9 = ±6
⇒ 3y - 9 + 9 = 6 + 9
⇒ 3y = 15
⇒ 3y/3 = 15/3
⇒ y = 5
⇒ 3y - 9 + 9 = -6 + 9
⇒ 3y = 3
⇒ 3y/3 = 3/3
⇒ y = 1