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Illusion [34]
4 years ago
15

Inside a square with side length 10, two congruent equilateral triangles are drawn such that they share one side and each has on

e vertex on a vertex of the square. What is the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles?

Mathematics
1 answer:
Sphinxa [80]4 years ago
4 0

Answer:

5 length

Step-by-step explanation:

The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share  one side of the square  BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.

So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.

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3 years ago
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Heights​ (cm) and weights​ (kg) are measured for 100 randomly selected adult​ males, and range from heights of 139 to 192 cm and
Bumek [7]

Answer:

The weight of an adult male who is 158 cm tall is 59.32 kg.

Step-by-step explanation:

The regression equation representing the relationship between height and weight of a person is:

\hat y=-105+1.04 x

Here,

<em>y</em> = weight of a person (in kg)

<em>x</em> = height of a person (in cm)

The information provided is:

\bar x=167.77\ \text{cm}\\\bar y=81.54\ \text{cm}\\r(X, Y)=0.201\\p-value=0.045

The significance level of the test is, <em>α</em> = 0.01.

The hypothesis to test the significance of the correlation between height and weight is:

<em>H₀</em>: There is no relationship between the height and weight, i.e. <em>ρ</em> = 0.

<em>Hₐ</em>: There is a relationship between the height and weight, i.e. <em>ρ</em> ≠ 0.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level, then the null hypothesis will be rejected and vice-versa.

According to information provided:

<em>p</em>-value = 0.045 > 0.01

The null hypothesis will not be rejected at 1% level of significance.

Thus, concluding that there is no relationship between the height and weight.

Compute the weight of an adult male with height, <em>x</em> = 158 cm as follows:

\hat y=-105+1.04 x

  =-105+(1.04\times 158)\\=-105+164.32\\=59.32

Thus, the weight of an adult male who is 158 cm tall is 59.32 kg.

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3 years ago
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Find the area of a triangle whose height is 2x and base is 2x + 2.
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Answer:2x^{2}+2x


Step-by-step explanation:

1. You must apply the formula for calculate the area of a triangle, which is shown below:

Area=\frac{base*height}{2}

2. You know the height and the base, which are given in the problem. Then, you only need to substitute them into the equation shown above and simplify it, as following:

Area=\frac{2x(2x+2)}{2}

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L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

L,M,N are midpoints altitude to ac​

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