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Illusion [34]
3 years ago
15

Inside a square with side length 10, two congruent equilateral triangles are drawn such that they share one side and each has on

e vertex on a vertex of the square. What is the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles?

Mathematics
1 answer:
Sphinxa [80]3 years ago
4 0

Answer:

5 length

Step-by-step explanation:

The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share  one side of the square  BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.

So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.

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Lera25 [3.4K]
1 7/9 - 4/9

Convert 1 7/9 to an improper fraction:

16/9 - 4/9

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12/9

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1 1/3
7 0
3 years ago
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What is an equation of the line that passes through the points (4,4) and (8.1)
andrey2020 [161]

Answer:

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Step-by-step explanation:

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<u>Find the line, using point-slope form and point (4, 4):</u>

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2 years ago
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ddd [48]

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3 0
3 years ago
Solve 5x - 8y = 11 for y.
disa [49]

Answer:

y = \frac{5x-11}{8}

Step-by-step explanation:

Given

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3 0
3 years ago
I need help with problem
pychu [463]

Answer:

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Step-by-step explanation:

First, factorize it.

That is equal to 4x(x-3)

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