Question

The sum of four consecutive odd integers is –72. Write an equation to model this situation, and find the values of the four integers. n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –19; n + 4 = –17; n + 6 = –15 n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –23; n + 4 = –25; n + 6 = –27 n – (n + 2) – (n + 4) – (n + 6) = –72; n = –20; n + 2 = –18; n + 4 = –16; n + 6 = –14 n + (n – 2) + (n – 4) + (n – 6) = –72; n = – 21; n – 2 = –23; n – 4 = –25; n – 6 = – 27

Answer 1

n + n + 2 + n + 4 + n + 6 = –72

4n +12 = -72

subtract 12 from each side

4n = -84

divide by 4

n = -21

Answer: -21,-19,-17,-15