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miss Akunina [59]
4 years ago
15

Haley used unit cubes to build a rectangular prism that is 5 units long, 3 units wide, and 4 units tall. Jeremiah used unit cube

s to build a rectangular prism that has twice the volume of Haley's prism. Jeremiah's prism is 4 units long and 3 units wide. How tall is Jeremiah's prism?
Mathematics
1 answer:
ad-work [718]4 years ago
8 0

Answer:

10 units

Step-by-step explanation:

Let us find the volume of Haley's prism and compare it with the volume of Jeremiah's.

The volume of Haley's prism is:

V = 5 * 3 * 4 = 60 cubic units

Jeremiah's prism has twice the volume of Haley's:

V(J) = 2 * 60 = 120 cubic units

This implies that:

120 = 4 * 3 * h

where h = height of prism

=> 120 = 12h

=> h = 120 / 12 = 10 units

Jeremiah's prism is 10 units tall.

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Karissa rides her bicycle for 4 hours and is 22 miles from her house. After riding for 8 hours, she is
inysia [295]

Answer:

5.5

Step-by-step explanation:

We nned to divide to solve this!!

22/4 = 5.5

She is going 5.5 mph!!

Have an amazing day!!

Please rate and mark brainliest!!!!

8 0
2 years ago
When shopping for a personal loan, why is it important to limit the amount of loan applications you submit?
Korvikt [17]

Answer:

The best answer is actually, When shopping for a loan, do not submit too many applications. Each time you submit an application, the lender will do a hard inquiry on your credit score. Having too many hard inquiries at one time will negatively affect your credit and raise your interest rate.

this is 100% correct

4 0
3 years ago
A polynominal function that describes an enclosure is v(x)=1500x_x2 where x is the length of the fence in feet what is the maxim
Maksim231197 [3]

Answer:

The answer is below

Step-by-step explanation:

A polynominal function that describes an enclosure is v(x)=1500x-x2 where x is the length of the fence in feet what is the maximum area of the enclosure

Solution:

The maximum area of the enclosure is gotten when the differential with respect to x of the enclosure function is equal to zero. That is:

V'(x) = 0

V(x) = x(1500 - x) = length * breadth.

This means the enclosure has a length of x and a width of 1500 - x

Given that:

v(x)=1500x-x². Hence:

V'(x) = 1500 -2x

V'(x) = 0

1500 -2x = 0

2x = 1500

x = 1500 / 2

x = 750 feet

The maximum area = 1500(750) - 750² = 562500

The maximum area = 562500 feet²

3 0
3 years ago
I need help Please help.
asambeis [7]

Answer:

Step-by-step explanation:

Number of students 10

Problem 1. $625 for the bus hire per friday, So 625*4=$2500

Problem 2. 2500/25=$100 each for the whole 4 weeks

Problem 3.

10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each

20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each

30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each

41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each

Hope this is correct

8 0
3 years ago
The distance between points (5,9) and (-7,-7)
ankoles [38]
You need to find the change in x and y 

change in x = 12 
change in y = 16 

to find the distance you use a^2+ b^2 = c^2
or in this case x^2 + y^2 = d^2

144+256 = 400 

\sqrt{400}

=20 
so distance equals 20


I hope this helps!
4 0
3 years ago
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