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3 years ago

Describe two diffrent ways to solve negative 10=1 fourth(8y-12)

1 answer:

6 0

The given equation is better written as

-10 = 1/4*(8y-12)

The first way of the solution is as follows:
Distribute 1/4 to the inside equation of the parenthesis.
-10 = 2y - 3
2y = -10 + 3 = -7
y = -7/2 = -3.5

The second way of the solution is as follows:
Cross-multiply the denominator a the right side to the left side.
-10*4 = 8y - 12
-40 = 8y - 12
8y = -40 + 12 = -28
y = -28/8 = -3.5

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Sally has six more 34 cent stamps than 52 cent stamps. If her stamps amount to 11.50 how many of each stamp does she have?

Yuliya22 [10]

Let x be the number of 52 cent stamps that Sally has and let y be the number of 34 cent stamps that she has.

Then,

52x + 34y = 1150 --- (1)

Also, she has six more 34 cent stamps than 52 cent stamps.

Therefore, y = x + 6

(1) becomes

52x + 34(x + 6) = 1150

52x + 34x + 204 = 1150

86x + 204 = 1150

86x = 1150 - 204

86x = 946

x = 11

and y = 11 + 6 = 17

Hence, Sally has eleven 52 cent stamps and seventeen 34 cent stamps.

6 0

3 years ago

Read 2 more answers

Match the like terms please!! giving brainliest to the right answer

evablogger [386]

Answer:

5x=256x

5xy= -xy

(3rd) -2x^2y=4x^2y(1st)

5y=3y

(5th) x^2y^2=(3rd) 2x^2y^2

(6th) 3y^2= 5y^2(5th)

Step-by-step explanation:

Hope you understand. Please mark as the brainliest.

5 0

3 years ago

Find the midpoint between A and B, given that A=(-1,5) and B=(-3,-7)

Kamila [148]

Hello here is a solution :
<span> midpoint between A and B,is :C( (Xa+xb)/2; (ya+yb)/2)
C( (-1-3)/2;(5-7)/2)
C(-2 ; -1)</span>

6 0

4 years ago

3×-5=16 and 3×=21

larisa [96]

Step-by-step explanation:

because we can also find out the value of x in second equation like this

3x=21

x=21/3

x=7

8 0

3 years ago

Read 2 more answers

an electrition charged $70 for 2 hours of work and 115 for 5hours of work write an equtionto find the cost for y and xk

Westkost [7]

$\bf \begin{array}{ccll} \stackrel{x}{hours}&\stackrel{y}{cost}\\ \cline{1-2} 2&70\\ 5&115 \end{array}~\hspace{10em}(\stackrel{x_1}{2}~,~\stackrel{y_1}{70})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{115}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{115-70}{5-2}\implies \cfrac{45}{3}\implies 15$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-70=15(x-2)\implies y-70=15x-30 \\\\\\ y=15x+40\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

as you already know, a direct proportional variation has a constant of variation "k", y = kx, which in this case that'd be the slope, namely 15.

7 0

3 years ago