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egoroff_w [7]
3 years ago
12

The Rogers family and the Brooks family each used their sprinklers last summer. The Rogers family's sprinkler was used for 30 ho

urs. The Brooks family's sprinkler was used for 25 hours. There was a combined total output of 1775 L of water. What was the water output rate for each sprinkler if the sum of the two rates was 65 L per hour?
Mathematics
1 answer:
timurjin [86]3 years ago
4 0

Step-by-step explanation:

what happens if there is excess or deficit of proteins in our body

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On a number line ,1.42 would be located.choose all answer that make a true statement
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Answer: A, D

Explanation:
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Which expression represents a number that is four times as large as the sum of
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Answer:

(160+8)×4

is the answer

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3 years ago
Drag steps of the solution into order to solve for x in the equation 6(x-5) = 54
telo118 [61]

The steps of the solution into order to solve for x in the equation 6(x-5) = 54 are:

  • A. 6x – 30 = 54
  • B. 6x = 84  
  • D. x = 14

Given the expression 6(x-5) = 54

Expand the expression in parenthesis using the distributive law;

6x - 6(5) = 54

6x - 30 = 54

Add 30 to both sides

6x - 30 + 30 = 54 + 30

6x = 84

Divide both sides by 6

6x/6 = 84/6

x = 14

Therefore the steps of the solution into order to solve for x in the equation 6(x-5) = 54 are:

  • A. 6x – 30 = 54
  • B. 6x = 84  
  • D. x = 14

Learn more on equations here; brainly.com/question/2972832

7 0
2 years ago
The diagram shows a right-angled triangle.
Margarita [4]
1/sin(38)*7=11.4
Hope it helps
6 0
3 years ago
A box has five items, three good and two defective. three items are selected at random without replacement. let x be the number
user100 [1]
This problem can be solved from first principles, case by case.  However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.

Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then 
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where 
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected

Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}

Therefore the 
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}

7 0
3 years ago
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