Answer:
D. They might order a greater number of gallons with jugs or with barrels, depending on various factors like the demand rate, ordering cost, and holding cost.
Explanation:
Let us assume the following things
D be the demand rate
P be the Unit cost
H be the holding cost per gallon per months
S be the ordering cost
Now the economic order quantity is
EOQ units = Q = √(2DS ÷ (H))
Therefore, the order quantity would be based upon demand rate, ordering cost and holding cost.
So the last option is correct
The D/E ratio indicates how much debt a company is using to finance its assets relative to the value of shareholders' equity
Answer:
E) $2,400
Explanation:
optimal order quantity = sqrt{(2*D*S)/H}
= sqrt{(2*36,000*$80)/$4}
= $1,200
number of orders per year = $36,000/$1,200
= $30
total ordering cost = $30*$80
= $2,400
Therefore, The total ordering cost of inventory is $2,400.
Answer:
D. Tim consumes more hamburgers and fewer hot dogs.
Explanation:
For his utility to remain constant, Tim will neither consume more goods in total, nor spend more money than before.
Therefore, because the price of hot dogs has risen, while the price of hamburger has remained the same, he will now buy more hamburgers and less hot dogs, because eating more hamburgers and less hot dogs will not decrease his satisfaction, it will remain the same. We can also conclude from that both fast food products are perfect substitutes for Tim.
Answer: The change in revenue for the sale of 1 more doghouse $ 66.67 dollars
Explanation: Differential is a function that can be used to approximate function value with a great degree of accuracy. This is done by the following.
Mathematical definition of derivative: f'(x) = lim f(x+Δx) - f(x)/Δx.
If Δx is very small:
f'(x) . Δx ≅ f(x+Δx) - f(x)
Knowing that Δy ≅ f(x+Δx) - f(x) and the diferential of variable x can be written by dx as the variable y can be dy:
dy = f'(x) dx
which means that the differential dy is approximately equal to the change Δy, if Δx is very small.
For the question, R(x) = y(x) = 14,000ln(0.01x+1)
f'(x) = ![\frac{d[14,000.ln(0.01x+1)]}{dx}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5B14%2C000.ln%280.01x%2B1%29%5D%7D%7Bdx%7D)
Using the chain rule, the derivative will be:
f'(x) = 14,000.
dy = 14,000..dx
dx is the change in x. For the question, the change is 1 (1 more doghouse) and x is 110:
dy = 14,000
dy = 
dy = 66.67
The change in revenue is $66.67 dollars.
