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frozen [14]
3 years ago
12

David invests $7000 in two different accounts. The first account paid 4 %, the second account paid 8 % in

Mathematics
1 answer:
Irina-Kira [14]3 years ago
6 0

What we know:

I  = Invest (so we dont mess up on interest.)

So, I = $7,000

First Account is 4%

Second Account is 2%

End of the year David Earns $476 in interest

With percent's you can always turn them into a decimal.

--------------------------------------------------------------------------------------------------------------

The Question: How much was in each account?

--------------------------------------------------------------------------------------------------------------

Step by Step Answer:

I = amount invested at 4%

4% = 0.40

8% = 0.80

0.40 - $7,000 = 6999.6

0.80 - 6999.6 = 6998.8

6998.8 - 476

Amount in both accounts in total is 6522.80.

--------------------------------------------------------------------------------------------------------------

HOPE THIS HELPS! =3

HAVE A FANTASTIC DAY!

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\frac{Height\ of \ object}{Height\ of \  shadow}

Let h be the height of the flagpole:

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3 years ago
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

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\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

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<h3>What is volume?</h3>

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To know more about volume follow

brainly.com/question/1972490

#SPJ1

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