1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Flauer [41]
3 years ago
7

Alice has an income of $52,000. She has an $8,300 exemption for her dependents. Her deductions are $2,560 for medical expenses a

nd, as a teacher, $250 for educational supplies.
What is her net taxable income?

A- $43,270
B- $39,620
C- $40,890
D- $38,100
Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

C-$40,890

Step-by-step explanation:

You might be interested in
The sum of 3 numbers is 64. The second number is 3 more than the first. The third number is 11 less than twice the first. Find t
Arlecino [84]
<span>Three numbers can be defined as x, y, and z.
x + y + z = 64
y = x+3
z = 2x - 11
.
substitute for y and z
x + (x+3) + (2x-11) = 64
4x -8 = 64
4x = 72

x = 18
.
y = x+3 = 21
z = 2x -11 = 2(18) -11 = 36-11 = 25
.
x + y + z = 18 + 21 + 25 = 64
Correct.
.
Answer: The three numbers are 18, 21, and 25.</span>
4 0
3 years ago
Find (4/7y-2 + 7y/2-7y)(Y+5/6 - y +3/6)
Phoenix [80]
Isn't that a binomial problem
8 0
3 years ago
Show how <br> -1(x - 3)^2 + 4 is equal to <br> -x^2 +6x - 5
Lyrx [107]

Answer:

Step-by-step explanation:

Expand:

-1(x^2-6x+9)+4=-x^2+6x-9 + 4 =  -x^2 + 6x - 5

4 0
3 years ago
Read 2 more answers
Will adding 3 different prime numbers result in a prime number?
Elden [556K]
Well, when you think about it a random set of prime numbers would be 1,3,5,7,11,13...
If you add 1+3+5 you get 9 which isn't a prime number.
Another example is 7+11+13 you get 31 which is a prime number.
So to answer your question: it depends on the type of prime numbers that you use
4 0
3 years ago
Suppose we are playing draw poker. we are dealt (from a well-shuffled deck) five cards, which contain four spades and another ca
77julia77 [94]
Assuming a standard deck, we started with 52 prior to dealing, then drew 4 spades and 1 non-spade. This leaves 47 cards in the deck. From these 47, we hope to draw another spade. The deck originally started with 13 spades, and after dealing the five cards, the remaining deck contains 9 spades. The probability of drawing one of these 9 cards from the deck of 47 is

\dfrac{\binom91\binom{38}0}{\binom{47}1}=\dfrac9{47}

That is, we want any 1 spade from the 9 spades available; we don't want any of the other 38 non-spades; and we're drawing 1 card from a total of 47.
4 0
3 years ago
Other questions:
  • How do I solve for his beginning to his starting point?
    6·1 answer
  • PLEASE HELP ME WITH THIS SHOW YOUR WORK AND YOU’ll GET BRAINLIEST! 20 POINTS
    8·1 answer
  • What is the product? 2y/y-3 multiply 4y-12/2y+6
    15·1 answer
  • The 4 people in your crew each spent 4 hours laying sod. How many person-hours is this?
    11·2 answers
  • Can you help on my math problems
    11·1 answer
  • <img src="https://tex.z-dn.net/?f=2%285y%20%2B%203%29%20-%204%287y%20%2B%201%29%20%3D%20%20-%2088" id="TexFormula1" title="2(5y
    15·2 answers
  • What is the total cost or sale price to the nearest cent? $50 tool set; 10% markup.
    11·1 answer
  • Parallel and perpendicular lines ​
    11·1 answer
  • Evaluate 2y²(x + y) when x = 1 and y = 5.
    8·1 answer
  • What is the meaning of the bottom number if the pitch of a roof is 2/7
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!