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4 years ago

Samuel paid $25.82 for gas this week, which was $3.47 less than he paid last week. How much had he paid last week?

Mathematics

1 answer:

Yuri [45]4 years ago

5 0

Samuel was paid $29.29 last week.

Hope this helps

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W + 1 = d and d = 3w solve by substitution

STALIN [3.7K]

Answer:

Step-by-step explanation:

Given

w + 1 = d...........equation 1

d = 3w ...............equation 2

Now putting d = 3w in equation 1

w + 1 = 3w

3w - w = 1

2w = 1

w = 1 / 2

putting w = 1 / 2 in equation 2

d = 1 / 2 * 3

= 3/2

Hope it helps :)

8 0

3 years ago

Read 2 more answers

I need to know the lengths of MN, NP, and PM

andrezito [222]

Answer:

MN = 12 units

NP = 16 units

PM = 20 units

Step-by-step explanation:

You can find MN and NP by counting on the graph. To find PM you will need to use the formula a^2 + b^2 = c^2 ( ^ stands for exponent)

MN and NP will be a and b.

Example: 12^2 + 16^2 = c^2

Simplify.

Example:

144 + 256 = c^2

144 + 256 = 400

Then find the square root of 400 which is 20.

To check your work put all of the sides into the formula and it should be true.

8 0

3 years ago

Read 2 more answers

Find the surface area

zalisa [80]

Answer:

Step-by-step explanation:

15 + 15 + 12 + 12 + 18 gives you 72 you add all the areas

6 0

3 years ago

A sum of money is divided in the ratio 2 : 3 : 7 .Given the largest share is $112,calculate the smallest share.

emmasim [6.3K]

Answer:

$32

Step-by-step explanation:

A sum of money is divided in the ratio 2:3:7.

Let the share of each individual be represented by 2x,3x,7x respectively.

The largest share (7x) is given as $112.

$7x = 112$

$=>x = \frac{112}{7}$

$=>x = 16$

So the respective shares are $2\times16,3\times16,7\times16$

In other words, the shares are 32,48,112.

So the smallest share is $32

4 0

3 years ago

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5$

3 0

3 years ago