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guapka [62]
3 years ago
13

Samuel paid $25.82 for gas this week, which was $3.47 less than he paid last week. How much had he paid last week?

Mathematics
1 answer:
Yuri [45]3 years ago
5 0
Samuel was paid $29.29 last week.

Hope this helps
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What is 23 divided by 12351
KIM [24]
The answer to your question is 537

       hope this helped let know if you need any more help
4 0
3 years ago
Find the zeros of the quadratic function. Solve by factoring. x^2+14x=-45
Reptile [31]

So, x^2 + 14 x + 49 - 4 = 0;

Then, we use the formula ( a + b )^2 = a^2 + 2ab + b^2;

We have ( x + 7 )^2 - 2^2 = 0;

Then, ( x + 7 )^2 - 2^2 = 0;

We use the formula a^2 - b^2 = ( a - b)( a + b );

We obtain ( x + 5 )( x + 9) = 0;

Then, x + 5 = 0;

x = -5;

x + 9 = 0;

x = - 9;

-5 and - 9 are the zeros of the quadratic function.

3 0
3 years ago
X-}y = 30, when y = 152 What is the value of x in the equation 8 80 © 200​
masya89 [10]

Answer:

182

Step-by-step explanation:

x-y =30

first we need to replace y woth the value given in the question.

x - 152 = 30

x = 30 + 152

x = 182

6 0
3 years ago
Find the taylor polynomial t3(x) for the function f centered at the number
olga nikolaevna [1]
e^{-4x}=\displaystyle\sum_{n=0}^\infty\frac{(-4x)^n}{n!}=1+(-4x)+\dfrac{(-4x)^2}2+\dfrac{(-4x)^3}6+\cdots
e^{-4x}=1-4x+8x^2-\dfrac{32x^3}3+\cdots

\sin2x=\displaystyle\sum_{n=0}^{\infty}\frac{(-1)^k(2x)^{2k+1}}{(2k+1)!}=(2x)-\dfrac{(2x)^3}6+\cdots
\sin2x=2x-\dfrac{4x^3}3+\cdots

e^{-4x}\sin2x=\left(1-4x+8x^2-\dfrac{32x^3}3+\cdots\right)\left(2x-\dfrac{4x^3}3+\cdots\right)
e^{-4x}\sin2x=2x-8x^2+\dfrac{44x^3}3+\cdots

\implies T_3(x)=2x-8x^2+\dfrac{44x^3}3
5 0
3 years ago
Can you help me it’s confusing
mojhsa [17]

Answer:

x=35

Step-by-step explanation:

You just add up all of the equations to equal 180

X+20+x+8+2x+12=180

4x+40=180

4x=140

x=35

6 0
3 years ago
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