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Inessa [10]
3 years ago
8

Area of solid shapes ​

Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

Surface-area. If a solid is composed of flat surfaces, such as the cube on the right, the surface area is simply the sum of the areas of the flat surfaces (called faces). So, for example, if a each edge of a cube has a length s, the area of one face is s2 since it is a square.

Step-by-step explanation:

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Is MNO=PQR? If so, name the congruence postulate that applies.
katrin2010 [14]

Answer:

B. Congruent - SSS

Step-by-step explanation:

Since, corresponding sides of both the triangles are congruent. Hence, both the triangles are congruent by SSS Postulate.

4 0
3 years ago
Two congruent angles have the same angle measure.
muminat

Answer:

True is the ans.

I hope it helps you.

7 0
3 years ago
Read 2 more answers
Eight decreased by three times the sum of a number and six<br><br> Write as an algebraic expression
Advocard [28]
8-3(x+6)

explanation:

it just makes sense lol but also bc “8 decreased by three” means “8 minus 3”

then “times” means “multiply”

then “a sum” means “addition”

then “a number” since we don’t know what a number is then we use “x”

“and” means “addition”

“a number and six” means “x+6”
3 0
3 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
What is 20% of 80?
Gala2k [10]

Answer:

55

Step-by-step explanation:

7 0
3 years ago
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