Answer:
= - 3n
Step-by-step explanation:
There is a common difference between consecutive terms, that is
- 6 - (- 3) = - 9 - (- 6) = - 12 - (- 9) = - 3
This indicate the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 3 and d = - 3 , thus
= - 3 - 3(n - 1) = - 3 - 3n + 3 = - 3n
The n th term is - 3n
Answer:
Step-by-step explanation:
tan Θ + tan 2Θ + √3 tan Θ tan 2Θ = √3
tan Θ + tan 2Θ = √3 - √3 tan Θ tan 2Θ
tan Θ + tan 2Θ = √3 ( 1 - tan Θ tan 2Θ)
(tan Θ + tan 2Θ) / (1 - tanΘ tan 2Θ) = √3
tan(Θ + 2Θ) = √3
tan 3Θ = tan () we know tan Θ = tan α; Θ = nΠ + α, n belongs to z
3Θ = nΠ + Π/3
Θ = nπ/3 + Π/9 for all n in Z