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2 years ago

6

Your friend says that 14.5% is equivalent to the decimal 14.5. explain why your friend is incorrect by comparing the fractional

equivalents of 14.5% and 14.5.
?????

1 answer:

adoni [48]2 years ago

7 0

14.5% = 0.145 = 145/1000

14.5 = 14500/1000

So 14.5% is a hundredth the size of 14.5, so they are not equal and the friend is incorrect.

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Women's heights are normally distributed with a mean given by p = 63.6 in. and a standard deviation given by o = 2.5 in. (a) If

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Step-by-step explanation:

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3 years ago

Which is true about this division problem? Select all

worty [1.4K]

Answer:

45 does not go into 285 evenly

The quotient contains a repeating decimal

The quotient is 6.3

Step-by-step explanation:

285/45 = 6.33333333

6.33333333 = 6.3

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3 years ago

Read 2 more answers

Molly runs each morning once around a circular path in her neighborhood. if the diameter of the path is 1.4 miles, how far does

Lemur [1.5K]

To work out the distance of the path, you need to find out the circumference.
Formula for circumference = pi multiplied by the diameter

So you simply do:
pi multiplied by 1.4 miles

And you should get:
4.39822971503... miles

Simply round the result to an appropriate value (e.g. 3 decimal places).

Answer: 4.398 miles (to 3dp)
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6 0

2 years ago

The effect of exposure to high-density automobile traffic either as a bicyclist or pedestrian was compared to minimal or no expo

Ber [7]

The option B is correct option. Thus, the Study design is used is a Case control study.

According to the statement

we have given that the incident cases of MI diagnosed in the emergency rooms of several hospitals is 500 and compared to 1,000 other subjects who visited the same emergency rooms for reasons other than cardiovascular and respiratory diseases.

And we have to find that the all these type of reports are formed which study method in medical science.

So, For this purpose, we know that the

A case control study is a study that compares two groups of people: those with the disease or condition under study (cases) and a very similar group of people who do not have the disease or condition (controls).

This study is perfectly match with the given condition.

So,

Case-control study is used in it by the below written way:

The study design relies on hospital-based recruitment of cases (persons with an MI) and controls (other patients in the emergency room who did not have cardiovascular and respiratory diseases which may be associated with air pollution). The exposure under investigation is a time-dependent measure of exposure to high-density automobile traffic in the days preceding the emergency room visit.

So, The option B is a correct option. The Study design is used is a Case control study.

Learn more about Case control study here

brainly.com/question/24087096

Disclaimer: This question was incomplete. Please find the full content below.

Question:

The effect of exposure to high-density automobile traffic either as a bicyclist or pedestrian was compared to minimal or no exposure to automobile traffic. It is hypothesized that direct exposure to automobile traffic has an effect on acute myocardial infarction (MI). This association was studied with 500 incident cases of MI diagnosed in the emergency rooms of several hospitals and compared to 1,000 other subjects who visited the same emergency rooms for reasons other than cardiovascular and respiratory diseases. All subjects were asked to report the amount of time that they spent exposed to high-density traffic over the past month prior to their hospital visit.

What type of study design is this?

A) Cross-sectional

B) Case-control

C) Retrospective cohort

D) Prospective cohort

E) Randomized clinical trial

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5 0

1 year ago

The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl

Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

= 1 - 0.004

= 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is not color- blind is,

P(not CBM) = 1 - P(CBM)

= 1 - 0.004

= 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

$P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times P(\text{not CBW})\\ = 0.93 \times 0.996 \\= 0.92628\\\approx 0.9263$

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

$P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737$

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0

3 years ago