Answer:
c is the correct answer
Step-by-step explanation:
because i worked it out
Step-by-step explanation:
Given equations:
y = x² + 3x - 29 ------ (i)
y = 2x - 9 ---------------- (ii)
Now to solve this problem, we must determine the value of x and y;
Equate equations 1 and 2;
x² + 3x - 29 = 2x - 9
x² + 3x - 2x - 29 + 9 = 0
x² + x - 20 = 0
x² + 5x - 4x - 20 = 0
x(x + 5 ) - 4(x + 5) = 0
(x - 4) (x+ 5) = 0
x - 4 = 0 or x + 5 = 0
x = 4 or x = -5;
So; solve for y now;
y = 2x - 9
input x = 4 or x = -5;
y = 2(4) - 9 or y = 2(-5) - 9
y = -1 or y = -19
X= 75/2
Y=0
That is the answer to your question I used Photomath to help me
Answer:
a.
-6a²/ b
b.
5y³
Step-by-step explanation:
a
-6a²b⁻¹
-6a²/ b
b.
5/ y⁻³
5 / 1/ y³
5 * y³/1
5y³
|2x + y - 3z|
Plug in the values
|-4 + 10 - 9|
= |-3|
= 3
