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3 years ago

QUESTION 5 · 1 POINT

Mathematics

1 answer:

natali 33 [55]3 years ago

3 0

Answer:

( x - 1) ( 2x + 3)

Step-by-step explanation:

It's actually the other way round.

2x^2- + x - 3

( 2x^2 - 2x) + (3x-3)

2x ( x-1 ) + 3( x-1)

( x - 1)(2x+3)

Its the other way around

HOPE IT HELPED

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Log3 a/3 = ??????????????????????????

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We have that
Log3 a/3
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we know that
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so
loga(x)=logb(x)/logb(a)
Substitute in values for the variables in the change of base formula

in this problem
b=10
a=3
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log3(a/3)=[log (a/3)]/[log (3)]

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Answer:

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What is the area of a rectangle that has the base of 5 centimeters and a height of 2 centimeters?

Alex_Xolod [135]

Answer:

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22. Find the perimeter and area.

zmey [24]

Answer:

Part 22) The area is $A=15a^3b^6\ units^2($ and the perimeter is $P=10a^2b^4+6ab^2\ unit$

Part 24) The area is $A=16m^3n\ units^2$ and the perimeter is $P=24mn\ units$

Part 26) The area is equal to $A=9\pi x^6y^{2}\ units^2$

Step-by-step explanation:

Part 22) Find the perimeter and area

step 1

The area of a rectangle is equal to

$A=LW$

we have

$L=5(a^2)(b^4)\ units$

$W=3(a)(b^2)\ units$

Remember that

When multiply exponents with the same base, adds the exponents and maintain the base

substitute in the formula

$A=(5(a^2)(b^4))(3(a)(b^2))$

$A=15a^3b^6\ units^2$

step 2

The perimeter of a rectangle is equal to

$P=2(L+W)$

we have

$L=5(a^2)(b^4)\ units$

$W=3(a)(b^2)\ units$

substitute in the formula

$P=2(5(a^2)(b^4)+3(a)(b^2))$

$P=10a^2b^4+6ab^2\ unit$

Part 24) Find the perimeter and area

step 1

The area of triangle is equal to

$A=\frac{1}{2}bh$

where

$b=8mn\ units$

$h=4m^2\ units$

Remember that

When multiply exponents with the same base, adds the exponents and maintain the base

substitute the given values

$A=\frac{1}{2}(8mn)(4m^2)$

$A=16m^3n\ units^2$

step 2

Find the perimeter

I will assume that is an equilateral triangle (has three equal length sides)

The perimeter of an equilateral triangle is

$P=3b$

where

$b=8mn\ units$

substitute

$P=3(8mn)$

$P=24mn\ units$

Part 26) Find the area

The area of a circle is equal to

$A=\pi r^{2}$

where

$r=3x^3y\ units$

Remember the property

$(a^{m})^{n}=a^{m*n}$

substitute in the formula the given value

$A=\pi (3x^3y)^{2}$

$A=9\pi x^6y^{2}\ units^2$

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3 years ago

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Dafna1 [17]

They have a scale factor of 5:6 so first we need to find the perimeter of KLM:
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Then apply the scale factor of 5:6:
$\frac{5}{6} = \frac{x}{42}$
Set the denominators equal:
$\frac{35}{42} = \frac{x}{42}$
So we see that the perimeter of GHJ is 35.

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