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d1i1m1o1n [39]
4 years ago
10

The Scholastic Aptitude Test (SAT) is a standardized test for college admissions in the U.S. Scores on the SAT can range from 60

0 to 2400. Suppose that PrepIt! is a company that offers classes to help students prepare for the SAT exam. In their ad, PrepIt! claims to produce "statistically significant" increases in SAT scores. This claim comes from a study in which 427 PrepIt! students took the SAT before and after PrepIt! classes. These students are compared to 2,733 students who took the SAT twice, without any type of formal preparation between tries. We conduct a hypothesis test and find that PrepIt! students significantly improve their SAT scores (p-value < 0.0001). Now we want to determine how much improvement we can expect in SAT scores for students who take the PrepIt! class. Which of the following is the best approach to answering this question? Group of answer choices Use the sample mean 29 to calculate a confidence interval for a population mean. Use the difference in sample means (500 − 529) in a hypothesis test for a difference in two population means (or treatment effect). Use the difference in sample means (500 − 529) to calculate a confidence interval for a difference in two population means (or treatment effect). Use the difference in sample means (29 and 21) in a hypothesis test for a difference in two population means (or treatment effect).
Mathematics
1 answer:
seropon [69]4 years ago
4 0

Answer:

Use the difference in sample means (500 − 529) in a hypothesis test for a difference in two population means (or treatment effect).

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Answer:

  1, 9

Step-by-step explanation:

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Esteban has a big jar of change in his room. He has 600 coins total, and 240
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  You can set up a proportion to solve for the percentage of the coins that are pennies. Of course, there are alternate methods as well, but this is one method. First, you define the percentage of the coins that are pennies to be equal to a variable, such as x. Next, you write 240/600 = x/100, due to how "x" is the amount out of 100 (since per cent is for every cent (out of 100)), and 240 would correspond to x while 600 would correspond to 100. This proportion may also be written as 100/x = 600/240, or 240/x = 600/100. In order to solve for x, you use cross-products, or you multiply each denominator by the numerator of the other fraction. You will be left with a numerical value that's equal to a number times x, and then you divide both sides of the equation by the coefficient of x in order to isolate x. As a result, you will have the percentage of the coins that are pennies to be your answer. Remember to write the units for every numerator and denominator in your proportion.
8 0
3 years ago
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A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys
expeople1 [14]

Answer:

The probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107

Step-by-step explanation:

Consider the provided information.

It is given that mean is 440 seconds and standard deviation is 60 seconds.  

z factor for less than 302 seconds would be:  z=\frac{x-\mu}{\sigma}

z = (302 - 440) / 60 = -2.3

The probability of getting a z factor of less than -2.3 = 0.0107 approximately.  

looking up in the z-table for a z factor of -2.3.

The probability of a student running the mile in less then 302 seconds would be 0.0107.

Hence, the probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107

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