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posledela
3 years ago
8

Shing brought 4 quiches for a party. Each quiche has 8 slices. There are 8 other people at the party. Everyone at the same numbe

r of slices. What is the greatest whole number each person could have eaten? How many slices could have been left over?
Mathematics
2 answers:
grandymaker [24]3 years ago
7 0
A lot of sixes brah dis
noname [10]3 years ago
6 0

Answer:

That would be 3

Step-by-step explanation:

(4*8)/9

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Avery has $3. She earns $1.20 for each chore she does. (She can complete fractions of
Sonja [21]

Answer:

She would have to do a chore 11.25 times

Step-by-step explanation:

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3 years ago
This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.
IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}

which would be

\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with 2^1=2 and ending with 2^6=64. So in sigma notation, this series is

\displaystyle\sum_{n=1}^6\frac1{2^n}

4 0
3 years ago
The Table Shows The Number Of Rows Of Bricks A Worker Can Lay In Different Numbers Of Hours
klemol [59]
The answer is 3. If you set it up in a T table and label x as the number of hours and y as the number of rows. Then use rise over run (y over x) the fractions simplify to 3 over 1.
4 0
3 years ago
Can someone’s please help me? (Ignore the work)
Zinaida [17]

Answer:

a^14b^12

Step-by-step explanation:

okay so lets distribute the 2

so you get -a^6b^10 and a^8b^2

add

7 0
3 years ago
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