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ANTONII [103]
3 years ago
13

If T(n) = 5 – 2n, what is the 2nd term?

Mathematics
1 answer:
Hoochie [10]3 years ago
7 0
T(n) = 5 - 2n
t(2) = 5 - 2(2)
t(2) = 5 - 4 = 1
<span>Answer would be 1</span>
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A plane flies 452 miles north and then 767 miles west. What is the magnitude and direction of the plane's resultant vector?
pshichka [43]

<u>Answer:</u>

The plane's resultant vector is 890.3 miles, at an angle of 59.5° west of north.

<u>Step-by-step explanation:</u>

• To find the magnitude of the resultant vector, we have to use Pythagoras's theorem:

\boxed{a^2 = b^2 + c^2}

where:

a ⇒ hypotenuse (= resultant vector = ? mi)

b, c ⇒ the two other sides of the right-angled triangle (= 452 mil North, 767 mi West).

Using the formula:

resultant² = 452^2 + 767^2

⇒ resultant =  \sqrt{452^2 + 767^2}

⇒ resultant = 890.3 mi

• To find the direction, we can find the angle (labeled <em>x</em> in diagram) that the resultant makes with the north direction:

tan (x) =\frac{767}{452}

⇒ x = tan^{-1} (\frac{767}{452} )

⇒ x = \bf{59.5 \textdegree}

∴ The plane's resultant vector is 890.3 miles, at an angle of 59.5° west of north .

6 0
2 years ago
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Which logarithmic equation is equivalent to the exponential equation below? 70.81 = ea
bixtya [17]
Loge 70.81 = a
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Solve the system by using the inverse of the coefficient matrix. -3x + 9y = 9 3x + 2y = 13 Group of answer choices
kirill [66]

Answer:

x= 3

y=2

Step-by-step explanation:

-3x + 9y = 9 ----------- equation 1

3x + 2y = 13--------------- equation 2

In  Matrix Form                            

\left[\begin{array}{cc}-3&9\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}9\\13\end{array}\right]                  

Let A = \left[\begin{array}{cc}-3&9\\3&2\end{array}\right]    X =  \left[\begin{array}{c}x\\y\end{array}\right]  and B =    \left[\begin{array}{c}9\\13\end{array}\right]  

Then Mathematically AX= B

or X= A⁻¹ B

Where A⁻¹ = Adjacent A/ mod of A

Adjacent A =   \left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]    

Mod Of A= -6 - (27) = -33 which is not equal to zero

so Putting These values in the given formula

X= 1/-33    \left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]      \left[\begin{array}{c}9\\13\end{array}\right]  

Now Multiplying Rows and Columns

   \left[\begin{array}{c}x\\y\end{array}\right] = -1/33    \left[\begin{array}{cc}2*9+- 9*13\\-3*9 +- 3*13\end{array}\right]

Solving the Matrix we get

  \left[\begin{array}{c}x\\y\end{array}\right] = -1/33  \left[\begin{array}{cc}18-117\\-27-39\\\end{array}\right]

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From Here we find x= 99/33 or 3

and y = 66/33= 2

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-8x>24

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\mathrm{Simplify},\\x

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VMariaS [17]

Answer:5(7) + 2(2) = 39

Step-by-step explanation:

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