The given graph is for a piecewise function consisting of two intervals:
(1) x ≤ 1 ⇒⇒⇒ the graph in this interval like <u>a cubic </u>function.
(2) x > 1 ⇒⇒⇒ the graph in this interval like <u>a quadratic </u>function
By comparing to the given options
<u>The answer is option c.</u>
Standard form is, hold a sec
x=2 is directix
that means it opens left or right
so we must use
(y-k)²=4p(x-h)
where vertex is (h,k) and p is distance from focus to vertex
also shortest distance from vertex to directix
the shortest distance from focus to directix is 2p
if p>0 then the parabola opens right
if p<0 then pareabola opens left
so
(-2,0) and x=2
the distance is 4
4/2=2
p=2
wait, positive or negative
focus is to the left of the directix so p is negative
p=-2
vertex is 2 to the right of the focus and 2 to the left of directix
vertex is (0,0)
so
(y-0)²=4(-2)(x-0) or
y²=-8x is da equation
not sure what form is standard tho
CAN SOMEONE PLEASE HELP ME ANSWER THIS QUESTION
Answer:
I don't understand the arrangement of the "table." I'll assume the question wants to know the values of b as a increase from 2 to 6.
Step-by-step explanation:
The resulting table is attached.
(5.6)(1.8) the answer is 10.08