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wariber [46]
3 years ago
9

State restrictions on the variable.

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0
There's one unforgivable taboo that transcends just about every branch of mathematics, and that's dividing by zero. Division by zero is undefined, so any fraction with a zero in its denominator is by definition absurd. For what values of x would the denominators on either of those fractions be zero? Those will define the restrictions on your variable.
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Given C is the midpoint of BD.
Nataly_w [17]

Answer:definition of midpoint, angle BCA is congruent to angle DCA

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3 years ago
Please help! Anyone! I've been stuck on these! Problem is below! A cylindrical fuel tank has a radius of 6.25 meters and a heigh
alexgriva [62]

Answer:

It may be 834.5m².........…………

3 0
2 years ago
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
chubhunter [2.5K]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

8 0
3 years ago
Which statement about the point (2, 0) is true?
ICE Princess25 [194]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The Correct choice is : C

\qquad \sf  \dashrightarrow \: it \:  \: is  \: \: on  \: \: the \: x  - axis

As we can observe, the y - coordinate ( ordinate ) of the given point (2 , 0) is 0. so it's obvious that it's distance from x - axis is Zero. In other words we can say that the point is lying on x - axis.

8 0
2 years ago
Read 2 more answers
PLSSSSSSSSS help just open it and help me PLSSSSSSSSS
Nastasia [14]
There is not question?
7 0
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