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wariber [46]
3 years ago
9

State restrictions on the variable.

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0
There's one unforgivable taboo that transcends just about every branch of mathematics, and that's dividing by zero. Division by zero is undefined, so any fraction with a zero in its denominator is by definition absurd. For what values of x would the denominators on either of those fractions be zero? Those will define the restrictions on your variable.
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A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent
BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

Solution also leaves the tank at a rate of 2L/hr, therefore in x hours, the amount of water that have left the tank = 2x

Hence the amount of water present in the tank at x hours is given as:

3 + 3x - 2x = 3 + x

The time taken to full the tank can be gotten from:

3 + x = 6

x = 6 - 3

x = 3 hr

b)

\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\  \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg

8 mg/ 6 L = 4/3 mg/L

8 0
3 years ago
3/4m^2-1 -5/2m+1 what is the answer and the solution
Ratling [72]
Solve Using the Quadratic Formula (m+ 4)(4m-2)=5(m+3)-10 ..... Use the quadratic formula to find the solutions.
5 0
3 years ago
Solve: X=4+(4x-4)
11111nata11111 [884]

Answer:

answer is 10

Step-by-step explanation:

3 0
3 years ago
You ask a neighbor to water a sickly plant while you are on vacation. Without water the plant will die with probability 0.75. Wi
Dafna1 [17]

Answer:

0.2915

Step-by-step explanation:

Let W represent water and D represent Dying probability

W = water

D = die

 

->If with water, it will die with probability 0.4

P(W & D) = 0.82 x 0.4 = 0.328

->Without water the plant will die with probability 0.75

P(W ' & D) = 0.18 x 0.75 = 0.135

Taking sum of the above values with water and without water.

P(D) = P(W & D) +  P(W ' & D) = 0.4643

P(W ' | D) = P(W ' & D) / P(D)

= 0.135 /0.463

= 0.2915 ≈ 29.15%

Thus, the probability the neighbor forgot to water is 0.2915

4 0
3 years ago
A certain disease occurs most frequently among older women. Of all age groups, women in their 60s have the highest rate of breas
Law Incorporation [45]

Answer:

The probability that a woman in her 60s has breast cancer given that she gets a positive mammogram is 0.0276.

Step-by-step explanation:

Let a set be events that have occurred be denoted as:

S = {A₁, A₂, A₃,..., Aₙ}

The Bayes' theorem states that the conditional probability of an event, say <em>A</em>ₙ given that another event, say <em>X</em> has already occurred is given by:

P(A_{n}|X)=\frac{P(X|A_{n})P(A_{n})}{\sum\limits^{n}_{i=1}{P(X|A_{i})P(A_{i})}}

The disease Breast cancer is being studied among women of age 60s.

Denote the events as follows:

<em>B</em> = a women in their 60s has breast cancer

+ = the mammograms detects the breast cancer

The information provided is:

P(B) = 0.0312\\P(+|B)=0.81\\P(+|B^{c})=0.92

Compute the value of P (B|+) using the Bayes' theorem as follows:

P(B|+)=\frac{P(+|B)P(B)}{P(+|B)P(B)+P(+|B^{c})P(B^{c})}

            =\frac{(0.81\times 0.0312)}{(0.81\times 0.0312)+(0.92\times (1-0.0312)}\\

            =\frac{0.025272}{0.025272+0.891296}

            =0.02757\\\approx0.0276

Thus, the probability that a woman in her 60s has breast cancer given that she gets a positive mammogram is 0.0276.

4 0
3 years ago
Read 2 more answers
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