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3 years ago

Find the coordinates of the midpoint of RS if R(-8,-3) and S(2,7) (-3,-2) (2,-3) (3,-2) (-3,2)

Mathematics

1 answer:

Tanzania [10]3 years ago

4 0

Answer:

Step-by-step explanation:

(-8+2)/2= -6/2 = -3

(-3+7)/2= 4/2 = 2

(-3, 2) midpoint

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Rasek [7]

Answer:

Move the decimal point 3 times to the left.

Step-by-step explanation:

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3 years ago

What is the domain and range please?

Stella [2.4K]

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3 years ago

Three out of four student surveyed in a school said they will vote for nuncio for class president. Predict how many of the 340 s

elena55 [62]

3/4 is .75. translate that to percentages, and you get 75%. This means that it is likely that 75% of the 340 students in total will vote for Nuncio.
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4 years ago

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Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!

forsale [732]

$1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}$

Step-by-step explanation:

The given equation is $4x^{2}-8x-1$

Let $a$ be the coefficient of $x^{2}$

Let $b$ be the coefficient of $x$

Let $c$ be the constant.

Then the roots α,β for the equation $ax^{2}+bx+c$ are $\dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}$

So,α= $\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}$

β= $\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}$ .

So the roots are $1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}$

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3 years ago

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DiKsa [7]

Volume of a sphere is 4/3(pi r ^3)

You were given d = 10 so r = 5

Then just plug and chug

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3 years ago

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