X/3 > 7 <== ur equation
multiply both sides by 3
x > 7 * 3
x > 21 <== ur solution
Answer:
there is no collision between the particles
Step-by-step explanation:
for the first particle
x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π
for the second particle
x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π
then for the collision
x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t
y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2
since 1/3 ≠ 2 there is no collision between the particles
Answer:
<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>
Step-by-step explanation:
Given equation is ![5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5](https://tex.z-dn.net/?f=5%2B20%5Ctimes%20%282%29%5E%7B2-3x%7D%3D10%5Ctimes%20%282%29%5E%7B-2x%7D%2B5)
<h3>To find the value of x :</h3>
First solving the given equation we have,
![5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5](https://tex.z-dn.net/?f=5%2B20%5Ctimes%20%282%29%5E%7B2-3x%7D%3D10%5Ctimes%20%282%29%5E%7B-2x%7D%2B5)
![5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5](https://tex.z-dn.net/?f=5%2B20%5Ctimes%20%282%29%5E%7B2-3x%7D-5%3D10%5Ctimes%20%282%29%5E%7B-2x%7D%2B5-5)
![20\times (2)^{2-3x}=10\times (2)^{-2x}](https://tex.z-dn.net/?f=20%5Ctimes%20%282%29%5E%7B2-3x%7D%3D10%5Ctimes%20%282%29%5E%7B-2x%7D)
![20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}](https://tex.z-dn.net/?f=20%5Ctimes%20%282%29%5E2.%282%29%5E%7B-3x%7D%3D10%5Ctimes%20%282%29%5E%7B-2x%7D)
![20\times 4.(2)^{-3x}=10\times (2)^{-2x}](https://tex.z-dn.net/?f=20%5Ctimes%204.%282%29%5E%7B-3x%7D%3D10%5Ctimes%20%282%29%5E%7B-2x%7D)
![80(2)^{-3x}=10\times (2)^{-2x}](https://tex.z-dn.net/?f=80%282%29%5E%7B-3x%7D%3D10%5Ctimes%20%282%29%5E%7B-2x%7D)
![\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B80%7D%7B10%7D%282%29%5E%7B-3x%7D%3D%5Cfrac%7B10%5Ctimes%20%282%29%5E%7B-2x%7D%7D%7B10%7D)
![8(2)^{-3x}=(2)^{-2x}](https://tex.z-dn.net/?f=8%282%29%5E%7B-3x%7D%3D%282%29%5E%7B-2x%7D)
![\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B%282%29%5E%7B-3x%7D%7D%7B%282%29%5E%7B-2x%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D)
( by using the property
)
( by using the property
)
![2^{-x}=\frac{1}{2^3}](https://tex.z-dn.net/?f=2%5E%7B-x%7D%3D%5Cfrac%7B1%7D%7B2%5E3%7D)
( by using the property
)
Since bases are same so powers are same
Therefore we can equate the powers we get x=3
<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>
Not enough information to actually do the problem, please provide more.
The function that is graphed is y = |x -2| + 3. The correct option is D. y = |x -2| + 3
<h3>Absolute value graph</h3>
From the question, we are to determine the function for the given graph
From the graph,
When x = 2, y = 3
The equation that satisfy this condition is
y = |x -2| + 3
NOTE: This function satisfies all the points on the graph
Hence, the function that is graphed is y = |x -2| + 3
Learn more on Absolute value graph here: brainly.com/question/17082317
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