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jenyasd209 [6]
3 years ago
7

The width of a rectangle is seven less than one-fifth its length. If L is used to represent the length of the rectangle, then ho

w could the width of the rectangle be represented in terms of L ?

Mathematics
2 answers:
Dima020 [189]3 years ago
6 0

Answer:check the pic

Step-by-step explanation:

Charra [1.4K]3 years ago
6 0

Answer:

W = L/5 - 7

Step-by-step explanation:

I think

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Last year the depth of the river was 4.2 feet deep. This year it dropped 25%. Find the depth of the river this year to cross it.
Novosadov [1.4K]

Answer:

The river is 3.15 feet deep.

Step-by-step explanation:

First let's recognize what we need to find: the depth of the river

We know last year the river was 4.2 feet deep, but it dropped 25%. This means we also need to find how much it dropped. To find this, we need to know what 25% of 4.2 is. Write an equation for this.

y = 25% of 4.2

y = 0.25 • 4.2

y = 1.05

This means that the river dropped 1.05 feet. To know its depth now, we need to subtract 1.05 from 4.2. Write an equation for this.

d = 4.2 - 1.05

d = 3.15

The river is 3.15 feet deep.

Hope this helps!

4 0
3 years ago
In 1928, when the high jump was first introduced as a women's sport at the Olympic Games, the winning jump for women was 70.0 in
sveta [45]

Answer: year 2194



Explanation:



1) Model the jump of the women:


i) initial jump = 70.0 in


ii) increase rate = 0.48% per year


iii) equation: h = 70.0(1 +0.0048)ⁿ


2) Model the jump of the men:


i) initial jump 86.5 inches.


ii) increase rate, 0.4%.


iii) equation: h = 86.5 (1 + 0.004)ⁿ


3) Equal the two equations (h = h) to find when the jumps will be equal:


i) 70.0(1 +0.0048)ⁿ = 86.5 (1 + 0.004)ⁿ


ii) 70.0(1.0048)ⁿ = 86.5 (1.004)ⁿ


ii) [1.0048ⁿ / 1.004ⁿ] = 86.5/70.0


iii) [1.0048/ 1.0040]ⁿ = 86.5/70.0


iv) n log (1.0048 / 1.0040) = log ( 86.5/70)


v) n = log (86.5/70) / log (1.0048/1.0040) ≈ 266


3) year = 1928 + 266 = 2194


That is in the year 2194

8 0
2 years ago
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scZoUnD [109]

Answer:

i dont  know much just do ur work correctly

Step-by-step explanation:

5 0
3 years ago
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Find the linearization L(x) of the function at a. f(x) = x^4 + 2x^2, a = 1
gregori [183]

The equation of the tangent line at x=1 can be written in point-slope form as

... L(x) = f'(1)(x -1) +f(1)

The derivative is ...

... f'(x) = 4x^3 +4x

so the slope of the tangent line is f'(1) = 4+4 = 8.

The value of the function at x=1 is

... f(1) = 1^4 +2·1^2 = 3

So, your linearization is ...

... L(x) = 8(x -1) +3

or

... L(x) = 8x -5

8 0
3 years ago
Hey im new, could someone help me???<br> evaluate 3(2)(-1)
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3(2)(-1)= 3×2×-1= 3×2=6×-1=-6 -6 is the answer

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3 years ago
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