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3 years ago

write the equation of a line that is perpendicular to the line y=-3/7-15 and that passes through the point (9,2)

Mathematics

1 answer:

SashulF [63]3 years ago

8 0

Answer:

Step-by-step explanation:

First substitue the coordinates to the equation so

x=9, y=2

you would get

2=-3/7(9) + b

we put b because we are trying to find the new slope

multiply the two numbers above

2=-3/6/7 + b

subtract the whole number from both sides

b= 5/6/7

in equation would be

y= -3/7 + 5/6/7

Let me know if there is an error.

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3 years ago

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3 years ago

Read 2 more answers

What is the area of the shaded portion of the circle?

SOVA2 [1]

Answer:

The first option is the correct one, the area of the shaded portion of the circle is

[/tex](5 \pi -11.6)ft^2[/tex]

Step-by-step explanation:

Let us first consider the triangle + the shadow.

The full area of the circle is the radius squared times pi, so

A= $(5 ft)^2 \cdot \pi \\25 ft^2 \cdot \pi$

Since $\frac{72^{\circ}}{360^{\circ}}=\frac{1}{5}$ , the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus

$A_1=\frac{1}{5}25 ft^2 \cdot \pi\\ =5 ft^2 \cdot \pi$

If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from $A_1$ .

The area of the triangle is given by

$A_{triangle}=\frac{1}{2}\cdot (2.9+2.9)ft \cdot 4 ft\\= 11.6 ft^2$

Thus the area of the shaded portion of the circle is

$A_1-A_{triangle}=5 \pi ft^2-11.6ft^2\\= (5 \pi -11.6)ft^2$

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3 years ago