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4 years ago

Asap plz help maxium points will mark brainliest

Mathematics

2 answers:

Sliva [168]4 years ago

8 0

Hey!

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Converse makes the statement true.

If a light bulb is yellow then it cost's $3. TRUE

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Inverse makes the statement false.

If a light bulb doesn't cost $3 then it isn't yellow. FALSE (Green is also $3)

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Contrapositive makes the statement false but switches around the inverse statement.

If a light bulb isn't yellow then it's not $3. FALSE (Green is also $3)

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Hope This Helped! Good Luck!

jeka57 [31]4 years ago

4 0

Given statement is False, if a light cost $3, it could be either Green or Yellow.

Converse: If the light bulb was Yellow, then the cost was $3 = True

Contrapositive makes both statements negative and switches the order of the original statement.

So something like: If the light bulb is not yellow, then the cost would not be $3 = False because two colors cost the $3.

Inverse makes both statements negative but keeps the same order.

Something like : If the light bulb did not cost$3 then the light bulb was not yellow = False because two colors cost the $3.

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Purple paint:mix 2 quarts of red paint for every3quarts of blue paint. How many blue paint is needed to make 35 quarts of purple

Phoenix [80]

Answer: 21 quarts of blue paint

Step-by-step explanation: To make a batch of purple paint, it is necessary 2 quarts of red and 3 quarts of blue, resulting in 5 quarts of purple.

So, to make 35 quarts of purple:

5x = 35

x = 7

It is needed, in total, 7 quarts of purple.

As, the ratio is 2 quarts of red to 3 quarts of blue:

Blue: 7 x 3 = 21

For 35 quarts of purple paint, it's necessary 21 quarts of blue paint.

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3 years ago

Find the slope and the y-intercept of the graph of y=11+1.5x.

Anni [7]

Honestly man i don’t know Im in 6th grade bro

6 0

3 years ago

Read 2 more answers

If you were asked to convert 75 m/s to km/hr, which conversation factors would you need to use. Select all that apply.

Vilka [71]

Answer:

You need to use A, B, and C.

Step-by-step explanation:

Let's treat the units as variables. I'll illustrate why in a moment.

$75 m/s =\frac{75m}{1s} \\\\\frac{75m}{1s}*\frac{1km}{1000m}=\frac{75m*km}{1000m*s}\\\\\frac{75m*km}{1000m*s}*\frac{60s}{1min}=\frac{(75*60)m*km*s}{1000m*s*min}\\\\\frac{4500m*km*s}{1000m*s*min}*\frac{60min}{1h}=\frac{4500m*km*s*min}{1000m*s*min*h}$

Now, as you can see, we have a giant mess of units to deal with. This is where we can treat the units like separate variables and use a bit of algebra to make our lives easier:

$\frac{4500m*km*s*min}{1000m*s*min*h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}\\\\\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}\\\\\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}\\\\\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}=\frac{4500}{1000}*\frac{km}{h}\\$

$\frac{4500}{1000}*\frac{km}{h}=\frac{45}{1}*\frac{km}{h}=45 \frac{km}{h}$

So, backtracking through that entire mess, we had to use $\frac{1km}{1000m} ,\frac{60s}{1min} ,\frac{60min}{1h}$ .

These correspond to the options of A, C, and B accordingly.

So you need to use A, B, and C.

8 0

3 years ago

How would I solve 16x^4-41x^2+25=0 ???

sveticcg [70]

$16{ x }^{ 4 }-41{ x }^{ 2 }+25=0$

${ x }^{ 4 }={ ({ x }^{ 2 }) }^{ 2 }\\ \\ 16{ ({ x }^{ 2 }) }^{ 2 }-41{ x }^{ 2 }+25=0$

First of all to make our equation simpler, we'll equal $x^{2}$ to a variable like 'a'.

So,

${ x }^{ 2 }=a$

Now let's plug $x^{2}$ 's value (a) into the equation.

$16{ ({ x }^{ 2 }) }^{ 2 }-41{ x }^{ 2 }+25=0\\ \\ { x }^{ 2 }=a\\ \\ 16{ (a) }^{ 2 }-41{ a }+25=0$

Now we turned our equation into a quadratic equation.

(The variable 'a' will have a solution set of two solutions, but 'x' , which is the variable of our first equation will have a solution set of four solutions since it is a quartic equation (<span>fourth-degree <span>equation) )

Let's solve for a.

The formula used to solve quadratic equations ;

$\frac { -b\pm \sqrt { { b }^{ 2 }-4\cdot t\cdot c } }{ 2\cdot t }$

The formula is used in an equation formed like this :
</span></span>
$t{ x }^{ 2 }+bx+c=0$

In our equation,

t=16 , b=-41 and c=25

Let's plug the values in the formula to solve.

$t=16\quad b=-41\quad c=25\\ \\ \frac { -(-41)\pm \sqrt { -(41)^{ 2 }-4\cdot 16\cdot 25 } }{ 2\cdot 16 } \\ \\ \frac { 41\pm \sqrt { 1681-1600 } }{ 32 } \\ \\ \frac { 41\pm \sqrt { 81 } }{ 32 } \\ \\ \frac { 41\pm 9 }{ 32 }$

So the solution set :

$\frac { 41+9 }{ 32 } =\frac { 50 }{ 32 } \\ \\ \frac { 41-9 }{ 32 } =\frac { 32 }{ 32 } =1\\ \\ a\quad =\quad \left\{ \frac { 50 }{ 32 } ,\quad 1 \right\}$

We found a's value.

Remember,

${ x }^{ 2 }=a$

So after we found a's solution set, that means.

${ x }^{ 2 }=\frac { 50 }{ 32 }$

and

${ x }^{ 2 }=1$

We'll also solve this equations to find x's solution set :)

${ x }^{ 2 }=\frac { 50 }{ 32 } \\ \\ \frac { 50 }{ 32 } =\frac { 25 }{ 16 } \\ \\ { x }^{ 2 }=\frac { 25 }{ 16 } \\ \\ \sqrt { { x }^{ 2 } } =\sqrt { \frac { 25 }{ 16 } } \\ \\ x=\quad \pm \frac { 5 }{ 4 }$

${ x }^{ 2 }=1\\ \\ \sqrt { { x }^{ 2 } } =\sqrt { 1 } \\ \\ x=\quad \pm 1$

So the values x has are :

$\frac { 5 }{ 4 }$ , $-\frac { 5 }{ 4 }$ , $1$ and $-1$

Solution set :

$x=\quad \left\{ \frac { 5 }{ 4 } \quad ,\quad -\frac { 5 }{ 4 } \quad ,\quad 1\quad ,\quad -1 \right\}$

I hope this was clear enough. If not please ask :)

3 0

3 years ago

Read 2 more answers

The scale model of a car is 5% of the size of the actual car. The length of

podryga [215]

<h3>Answer: 15 feet</h3>

Explanation:

x = length of the actual car in inches

5% of x = 9 inches

0.05x = 9

x = 9/(0.05)

x = 180 inches

Divide by 12 to convert from inches to feet.

180 inches = (180/12) feet = 15 feet

5 0

3 years ago