Answer:
(A)Show that the ratios StartFraction U V Over X Y EndFraction , StartFraction W U Over Z X EndFraction , and StartFraction W V Over Z Y EndFraction are equivalent.

Step-by-step explanation:
In Triangles WUV and XZY:

Therefore:

To show that the triangles are similar by the SSS similarity theorem, we have:

As a check:

The correct option is A.
Part A: The probability is 1/6. This is because there are six options in total, and only one of those options is 6.
Part B: The probability is 6/6, or alternatively 100%. This is because that the probability of rolling a 6 is 1/6, and the probability of rolling any of the other options is 5/6. Adding them together gives a probability of 6/6.
Part C: The probability is 5/6. This is because there are six options, and of those, five of them are not 6.
Answer:
x=40/9
Step-by-step explanation:

Answer:
ok sorry i could not put this into a formula im have to go but i will show you a really easy way.
Step-by-step explanation:
for number 1 i got (7,-1)
This is because there is a slope of 1/1 between these two points. so i plotted the two points on the graph. The distance between the two points is 4. so i followed the slope 4 times and thats what i got.
The correct way for doing number 1 is using the distance formula i believe but im running out of time
for the second one i got (3, -1/2)
we do this by using the midpoint formula.
The first picture is for number one and the second for number 2
if you have any questions feel free to ask in the comments
Answer:


Step-by-step explanation:
One is given the following function:

One is asked to evaluate the function for
, substitute
in place of
, and simplify to evaluate:



A recursive formula is another method used to represent the formula of a sequence such that each term is expressed as a function of the last term in the sequence. In this case, one is asked to find the recursive formula of an arithmetic sequence: that is, a sequence of numbers where the difference between any two consecutive terms is constant. The following general formula is used to represent the recursive formula of an arithmetic sequence:

Where (
) is the evaluator term (
) represents the term before the evaluator term, and (d) represents the common difference (the result attained from subtracting two consecutive terms). In this case (and in the case for most arithmetic sequences), the common difference can be found in the standard formula of the function. It is the coefficient of the variable (n) or the input variable. Substitute this into the recursive formula, then rewrite the recursive formula such that it suits the needs of the given problem,


