Hello,
Please, see the attached file.
Thanks.
Please, see the attached file.
Thanks.
I don't know how to solve these two types of questions: (x+y)(x-y)=20 and (z+z)(z+z)=63
1 answer:
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Answer:
41.04 meters
Step-by-step explanation:
The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. The initial position is given by A. The tree is denoted as C and the fence post is denoted as B. Since the use of sine rule will complicate the question, it will be easier to solve this question using the cosine rule. Therefore, cosine rule will be used to calculate the length of BC. The cosine rule is:
BC^2 = AB^2 + AC^2 - 2*AB*AC*cos(BAC).
The question specifies that AC = 70 meters, BAC = 25°, and AB = 35 meters. Plugging in the values:
BC^2 = 35^2 + 70^2 - 2(35)(70)*cos(25°).
Simplifying gives:
BC^2 = 1684.091844.
Taking square root on the both sides gives BC = 41.04 meters (rounded to two decimal places).
Therefore, the distance between the point on the tree to the point on the fence post is 41.04 meters!!!
Given a fragpole which makes a right angle with the point of observation with the angle of elevation as 50°.
Let x be the height of the flagpole, then
Therefore, the <span>equation that could be used to find the height of the flagpole is
</span><span>x/5 = sin 50</span>
Let x be the height of the flagpole, then
Therefore, the <span>equation that could be used to find the height of the flagpole is
</span><span>x/5 = sin 50</span>