All categories

2 years ago

I don't know how to solve these two types of questions: (x+y)(x-y)=20 and (z+z)(z+z)=63

Mathematics

1 answer:

Ksju [112]2 years ago

7 0

3 fdjfjddjdnsnfjdjfjdjdjdjdjdnekvidijrrjen ekfodi sifu shav csjrejfjejejjfjdffjdjdj

You might be interested in

How does a "for every" statement show a ratio comparison? (Example of a for every statement: There a 5 strawberries for every 6

mestny [16]

If you think of the "for every" as a : then it will make sense. So, replace the "for every" with a :.
So:
There are 5 strawberries for every 6 apples
Turns into
strawberries:apples = 5:6

5 0

2 years ago

Read 2 more answers

Write the equation of the blue line using slope intercept form (y=mx+b)

dalvyx [7]

Answer:

Step-by-step explanation:

X1=-4

Y1=7

X2=-3

Y2=6

(-2,0 ) X INTERCEPT

(0,-7)Y INTERCEPT OR B

M=6-7/-3+4

M=_1

Y=-1X+-7

5 0

1 year ago

Como resuelvo esto <br>(a+2)^3

Dmitry [639]

Answer:

a³+8

Step-by-step explanation:

4 0

2 years ago

How many per laps is that

ale4655 [162]

Do you have a picture so that ik what the track looks like

3 0

2 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

6 0

2 years ago