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elena-14-01-66 [18.8K]
3 years ago
8

I don't know how to solve these two types of questions: (x+y)(x-y)=20 and (z+z)(z+z)=63

Mathematics
1 answer:
Ksju [112]3 years ago
7 0

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Quentin purchased 5 arrowheads for $1.75 each. He
Lyrx [107]

Answer:

Quentin received $1.25 in change

Step-by-step explanation:

10-1.75(5)

10- 8.75

1.25

6 0
3 years ago
Read 2 more answers
Help and explain !!!!( Solve using the substitute method )
alex41 [277]

Answer:

x=13

y= -9

(13, -9)

Step-by-step explanation:

If we are solving using the substitution method, we can take the first equation and set it to y so y=4-x.

Then, we can take that equation and plug it into the bottom one so

3x+4(4-x)=3

Simplify:

3x+16-4x=3

-x=-13

x=13

We can then plug 13 into any of the two given equations (I am just going to plug it into the top one)

So, 13+y=4 which y= -9

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3 years ago
Solve. x^2 8x 25 = 0
kykrilka [37]
This equation is unsolvable.
x^2+8x+16=0
(x+4)^2+9=0
(x+4)^2= -9
anything to the power of whatever has to be greater than -1, it means it can be 0 or more but never a negative number. If it is a negative number, then it is false.
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3 years ago
Need Help ASAP u can see my test timer
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It would be the second one if you follow PEMDAS
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A spherical balloon has a ​-in. diameter when it is fully inflated. Half of the air is let out of the balloon. Assume that the b
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\frac{256}{3}  Pi

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