PLEASE HELP ME! I NEED ANSWER ASAP!!!

Neil has 3 partially full cans of white paint. They contain 1/3 gallon, 1/5 gallon and 1/2 gallon of paint. About how much paint

lorasvet [3.4K]

Answer:

31/30 or 1 1/30

Step-by-step explanation:

1/3+1/5+1/2

6 0

3 years ago

Find the area of the shaded region for the given figure in terms of x.

Vlada [557]

Answer:

Area of the shaded region = (6x + 3)

Step-by-step explanation:

Area of the shaded region = Area of the large rectangle - Area of the small rectangle

Area of the large rectangle = Length × Width

= (x + 2)(x + 2)

= (x + 2)²

= x² + 4x + 4

Area of the small rectangle = (x - 1)(x - 1)

= (x - 1)²

= x² - 2x + 1

Area of the shaded region = (x² + 4x + 4) - (x² - 2x + 1)

= 6x + 3

Area of the shaded region = (6x + 3)

4 0

3 years ago

Which function shows the final cost in dollars, y, for renting four trucks using personal insurance for x number of days? y = 27

butalik [34]

= 99.907 = 170x=123.908

8 0

3 years ago

Consider the region, R, bounded above by f(x)=x2−6x+9 and g(x)=−3x+27 and bounded below by the x-axis over the interval [3,9]. F

Salsk061 [2.6K]

Answer:

22.5

Step-by-step explanation:

The region R contains every point of the plane with coordinate x between 3 and 9, and with coordinate y positive such that y < f(x) and y < g(x).

We can note that both f and g are positive on [3,9] because g is a decreasing linear function and g(9) = 0, thus g is positive in every other point of the interval, and f(x) = (x-3)^2 is always positive excpept when x = 3, where it reaches the value 0.

The interception of the graphs takes place for a value x such that f(x) = g(x).

We compute x^2-6x+9 = -3x + 27, thus x^2-6x+9-(-3x + 27) = x^2-3x -18 = 0.

The roots of that quadratic function are

$r_1, r_2 = \frac{3 ^+_- \sqrt { 9 +72}}{2} = \frac{3^+_-9}{2}$ , thus r1 = 6, r2 = -3. We dont care about -3 because it is outside the interval, but we know that f and g graphs intersects on x = 6. Thus, we obtain, due to Bolzano Theorem:

On the interval [3,6), the function f in smaller because it takes the value 0 on x=3, while g is always positive.
On the interval (6,9]. the function g is smaller because it takes the value 0 on x=9, while f is always positive

Hence, the upper bound is f on the interval [3,6) and g on the interval (6,9]. While the lower bound is the 0 function.

We need to calculate the following integral, using Barrow's rule

$\int\limits^6_3 {x^2-6x+9} \, dx + \int\limits^9_6 {-3x+27} \, dx = (\frac{x^3}{3} - 3x^2 + 9x) |^6_3 + (\frac{-3x^2}{2} + 27x)|^9_6 = \\ (18 - 9) + (121.5-108) = 22.5$

As a result, the area of the region R is 22.5

6 0

3 years ago

Chi square Daphne likes to ski at a resort that is open from December through April. According to a sign at the resort, 20, perc

Marat540 [252]

Answer:

There is not enough evidence to suggest that the snow falls in Daphne's hometown does not follow the given distribution.

Step-by-step explanation:

The missing data for the random sample of 80 days between December and April with snowfall is:

Month Days

December 16

January 11

February 16

March 18

April 19

The Chi-square goodness of fit test would be used to determine whether the snow falls in Daphne's hometown followed the given distribution.

The hypothesis for the test can be defined as follows:

H₀: The snow falls in Daphne's hometown does not follow the given distribution.

Hₐ: The snow falls in Daphne's hometown followed the given distribution.

Assume that the significance level of the test is, α = 0.05.

The Chi-square test statistic is given by:

$\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}$

The value of Chi-square test statistic is computed in the Excel sheet below.

$\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}=8.383$

Compute the p-value as follows:

$\text{p-value}=P(\chi^{2}_{(4)}>8.383)=CHISQ.DIST.RT(8.383,4)=0.0785$

The p-value of the test is 0.0785.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

p-value = 0.0785 > α = 0.05.

The null hypothesis will not be rejected.

Conclusion:

There is not enough evidence to suggest that the snow falls in Daphne's hometown does not follow the given distribution.

4 0

4 years ago