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avanturin [10]
4 years ago
15

Expand and evaluate the series n=5 ai=2×i^2+3

Mathematics
1 answer:
Ksju [112]4 years ago
5 0
Hello,

a_{1}=2*1^2+3=2*1+3=2+3=5\\\\
 a_{2}=2*2^2+3=2*4+3=8+3=11\\\\
 a_{3}=2*3^2+3=2*9+3=18+3=21\\\\




see file jointed
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