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2 years ago

What is the value of x in the equation 8 + 4 = 2 (x -1)

Mathematics

1 answer:

melisa1 [442]2 years ago

8 0

Answer: x=7

Step-by-step explanation:

8 + 4 = 2(x - 1) combine like terms on the left side

12 = 2(x -1) Distribute on the right side

12 = 2x - 2 Add 2 to both sides

+2 +2

14 = 2x Divide both sides by 2

x= 7

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What is the arc length if Θ = 2 pi over 7 and the radius is 3 cm? A. 7 pi over 12

hodyreva [135]

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

$\theta=\frac{2\pi}{7} \\\\r=3\ cm$

An arc is a part of total circumference of circle and length of that arc is the measurement of linear distance.

Since we know the formula for "Length of an arc " , we get

$L=r\times \theta\\\\L=\frac{2\pi}{7}\times 3\\\\L=\frac{6\pi}{7}$

Hence, Option 'C' is correct.

6 0

2 years ago

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Goshia [24]

Im pretty sure the answer is a

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2 years ago

The graph of which function will contain the point(2,10)

kotegsom [21]

Answer:

point (2 , 10)

Y= 5X

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1 year ago

Find the area of a plane figure bounded by lines

natulia [17]

Answer: 4.5

Step-by-step explanation:

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6 ⇒ x² + x - 2 = 0 ⇒ (x + 2)(x - 1) = 0 ⇒ x = -2, x = 1

Now, integrate from x = -2 to x = 1

$\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,$ the bottom of the integral is -2

= $\int\limits^1_2 {x+6-x^{2}-2x-4 } \,$

= $\int\limits^1_2 {-x^{2}-x+2 } \,$

= $\frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,$

= $(\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))$

= $(\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)$

= $\frac{-9}{3} + \frac{3}{2} +6$

= -3 + 1.5 + 6

= 4.5

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2 years ago

Simplify (1/2k) (4k) + 12 2k 2 + 12 14k 2 2k + 12 14k

Lady bird [3.3K]

Answer:

(1/2) (4k) + 12 = 2k + 12

7 0

3 years ago