Answer:
Step-by-step explanation:
Problem One (left panel)
<em><u>Question A</u></em>
- The y intercept happens when x = 0
- That being said, the y intercept is 50. It was moving when the timing began.
<em><u>Question B</u></em>
The rate of change = (56 - 52)/(3 - 1) = 4/2 = 2 miles / hour^2 (you have a slight acceleration.
<em><u>Question C</u></em>
- 60 = a + (n-1)d
- 60 = 50 + (n - 1)*2
- 10/2 = (n - 1)*2/2
- 5 = n - 1
- 6 = n
The way I have done it the domain is n from 1 to 6
Question 2 (Right Panel)
<em><u>Question A</u></em>
The equation for the table is f(x) = 3x - 3 which was derived simply by putting all three points into y = ax + b and solving.
- f(0) = ax + b
- -3 = a*0) + b
- b = - 3
- So far what you have is
- f(x) = ax - 3
- f(-1) = a*(-1) - 3 but we know (f(-1)) = -6
- - 6 = a(-1) - 3 add 3 to both sides
- -6 +3 = a(-1) -3 + 3
- -3 = a*(-1) Divide by - 1
- a = 3
- f(x) = 3x - 3 Answer for f(x)
- The slope of f(x) = the coefficient in front of the x
- f(x) has a slope of 3
- g(x) has a slope of 4
<em><u>Part B</u></em>
- f(x) has a y intercept of - 3
- g(x) has a y intercept of -5
- f(x) has the greater y intercept.
- -3 > - 5
Answer:
a
Step-by-step explanation:
Answer:
y=0, x=1
Step-by-step explanation:
6x-3y= -6 ...... equation 1
y =2x+2 ..... equation 2
subtract 2x from both sides
y-2x=2x-2x+2
y-2x=2
6x-3y= -6
y-2x=2
Rearrange
6x-3y= -6 ........x1
-2x +y=2............x3
6x-3y= -6
-6x +3y=2
0y=0
y=0
substitute y=0 in equation 1
6x-3xo= -6
6x= -6
x-6/6
x = -1
The graph is Parabola or Graph of Quadratic Function.
The graph has minimum value, not maximum. So ( A ) is not correct for maximum part.
B is not correct for exponential part.
also C is not correct for discrete part as Quadratic graph is continuous.
So the answer is D.
